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I have found out about Coefficient of friction depends on slip ratio(which I am still not sure how to calculate) Friction determines maximum force exceeded to move car Friction depends from load on wheel … Friction prevents car from sliding However, I am not kinda sure how that all works - how to calculate each of the variables and forces(slip ratio, friction-determined maximum force for longitudal motion …

We know that friction helps in driving a car, but does this mean that a car can move faster on rough surfaces? Since the coefficient of friction is higher on rough surfaces? …

When driving a car, constant velocity is achieved when there is no net force acting upon the car. But does friction increase with speed, like air resistance? … In a world without air resistance, would constant velocity be achieved by applying a force to a car, to accelerate it to a desired speed, before applying less force that is equivalent to friction, so there …

Consider a car driving on a horizontal road, with some coefficient of friction, $\mu$. … When the driver releases the pedal, the same friction force accelerates the car backwards, but now there is no driving force, so the car drifts slowly to a halt. …

When it starts the impending motion of tyres is in the backward direction that's why friction is in the forward direction and the car starts moving. … But when the car engine turns off, the car stops after some time, but the condition of tyres are the same as in the previous case and friction must be in the forward direction. …

Static Friction - Only thing that can accelerate a train? My understanding of physics favors this later model for car as well. … But this model is completely wrong: no slip means no (kinetic) friction and no acceleration But why can't a tire accelerate a car when there is no slip, via static friction? …

I am trying to understand the nature and direction of friction force acting on from the ground a car driving up an incline. … The thrust force that acts on the car from the ground (supposedly friction as well?) should have magnitude $T=mg \cdot \text{sin}(\alpha) + \mu \cdot mg \cdot \text{cos}(\alpha) $. Here's my problem. …

I wanted to ask why doesn't the car move on a frictionless surface. Suppose you are on a frictionless surface When you press the accelerator the wheels start rotating and apply a force to the ground. … (because there is no friction). Now suppose there is some friction and I am walking on the ground. Can I apply some force greater than the limiting value of the friction of the ground? …

David Morin, in "Introduction to Classical Mechanics" says that friction does not exert a force on a car because the ground is fixed but that KE of the car is changing to internal kinetic energy in the … But pages earlier, he mentions the famous example of friction on a sliding book: friction does no work on the cars but does work on the book. although the ground is not moving in both cases. …

Let's say a car is driving at constant speed along a perfectly circular loop road. … Centripetal acceleration works toward the center of the circle, but the car is moving forward along the loop, perpendicularly to the car's acceleration. …

It is known that friction is given as : $F_{friction}=\mu F_n$ , where $F_n$ is the normal force, and $\mu$ is coefficient of friction. … I thought friction always opposes motion? How can a car accelerate with the same force (i.e. friction) which also causes it to slow down. If there is no friction, a car cannot accelerate? …

If a car moves using the friction force from the rotation of the wheels, shouldn't a car be unable to accelerate immediately after the car is at motion, since there will be a friction force of equal magnitude … which opposes the movement of the car. …

When the car is moving in a straight line, the tire pushes the road backwards and the road pushes the car forward. Because of the friction between the tire and the road, the car moves. … On the other hand, if the car is stopped on the road and I try to push it sideways, a friction from the road to the tires of the car will oppose my force. …

We are looking at a car driving along a horizontal road and at static friction, and how static friction translates to movement with the cars tires. … We are given the maximum static friction coefficient $\mu$ which is $0.6$. …

A car of mass $m$ is pushing head-on against a truck mass $2m$ from rest. The truck is pushing back. The tires are spinning on both. Will either move? … Since both have equal tires and the tires are both spinning, they have equal acceleration due to friction. …