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15 votes
5 answers
2k views

What does it mean for a physical quantity if its mixed second partial derivatives are not equal?

This goes for every problem (either in electromagnetism or fluid dynamics) that has to do with vector fields. Say we have a fluid flowing in a closed circular pipe (or an electromagnetic field, the ...
TheQuantumMan's user avatar
11 votes
2 answers
577 views

Is $∂_\mu + i e A_\mu$ a "covariant derivative" in the differential geometry sense?

I have heard the expression "$∂_\mu + i e A_\mu$" referred to as a "covariant derivative" in the context of quantum field theory. But in differential geometry, covariant derivatives have an ostensibly ...
WillG's user avatar
  • 3,566
7 votes
6 answers
15k views

Why is curl of current density $\nabla \times \vec{J}$ equal zero?

I am revisiting the derivation for $\nabla \cdot \vec{B} = 0$ in magnetostatics for the field $\vec{B}(\vec{r})$ of a charge $q$ at position $\vec{0}$ with velocity $\vec{v}$. It proceeds like \begin{...
GDumphart's user avatar
  • 207
6 votes
4 answers
3k views

What is the current of a capacitor when the derivative of voltage is undefined?

This is from the textbook I am reading: I know this equation for capacitors: $$i=C\cdot \frac { dv }{ dt }$$ Here is my question: how can diagram (a) be allowed if the derivative of the voltage ...
user42264's user avatar
5 votes
4 answers
386 views

Vector triple product with $\nabla$ operator

I came across the following expression in several books (especially in plasma physics literature while deriving the magnetic pressure): $$(\mathbf{\nabla} \times \mathbf{B})\times \mathbf{B} = \left(\...
kid_a's user avatar
  • 61
5 votes
5 answers
7k views

What is divergence?

What is divergence? I was learning about Maxwells equations and don't understand the divergence part of it. Can someone give an intuition of what divergence is in relation to maxwells equation. To ...
Ray Kay's user avatar
  • 1,660
5 votes
4 answers
5k views

Why are divergence and curl related to dot and cross product?

I've been reading Griffith's intro to electrodynamics and I've been a bit confused about his explanation of divergence and curl. I don't understand how divergence is the dot product of a gradient ...
Honors Level Maker's user avatar
5 votes
1 answer
5k views

What's the physical meaning of vector Laplacian of Electric field intensity?

Could someone explain to me the physical meaning of vector Laplacian of Electric field intensity? Where vector Laplacian means: $$\nabla^2 \mathbf{E} = \nabla(\nabla \cdot \mathbf{E}) - \nabla \times ...
Vents's user avatar
  • 51
4 votes
2 answers
2k views

Derivatives of Dirac delta function and equation of continuity for a single charge

For a single charge $e$ with position vector $\textbf R$, the charge density $\rho$ and and current density $\textbf{j}$ are given by: \begin{equation} \rho(\textbf{r},t)= e\,\delta^3(r-\textbf{R}(t))...
quark1245's user avatar
  • 1,412
4 votes
1 answer
230 views

Is there a quick way to calculate the derivative of a quantity that uses Einstein's summation convention?

Consider $F_{\mu\nu}=\partial_{\mu}A_\nu-\partial_\nu A_\mu$, I am trying to understand how to fast calculate $$\frac{\partial(F_{\mu\nu}F^{\mu\nu})}{\partial (\partial_\alpha A_\beta)}$$ without ...
Rescy_'s user avatar
  • 862
4 votes
1 answer
111 views

What does $\mathbf{A}\cdot\nabla$ mean here?

What does $\mathbf{A}\cdot\nabla$ mean in an expression like $(\mathbf{A}\cdot\nabla)\mathbf B$? I found this in Griffiths’ Classical Electrodynamics book and cannot figure it out.
Pranshu Khare's user avatar
4 votes
2 answers
157 views

Local symmetry restoration via a gauge field

In the book Quantum Field Theory for the Gifted Amateur, the author stated that, having a field that transforms locally via $\psi(x) \rightarrow \psi(x)e^{i \alpha(x)}$ will destroy local symmetry -...
AGawish's user avatar
  • 165
4 votes
2 answers
59 views

Where does one more '$\rm m$' come from in the units?

$$\nabla \times A = B$$ $A$ is vector magnetic potential, $\mathrm{Wb/m}$ $B$ is magnetic field intensity, $\mathrm{Wb/m^2}$ Where does one more m come from for $B$? Is that from the gradient operator ...
Clone's user avatar
  • 285
4 votes
1 answer
3k views

Is the differential form of Faraday-Henry equation ( Curl(E)= - dB/dt) always valid?

My textbook suggests that the integral form of the law is evident from experiments, while the differential form can be obtained by considering a closed curve, constant in time, so that it is ...
Francesco Bilotta's user avatar
4 votes
2 answers
271 views

Conventions regarding partial derivatives

Look at this expression: $$\frac{\partial}{\partial t} (V-\mathbf{v}\cdot\mathbf{A}).$$ This expression occurs in Griffiths EM book (4th ed, p.444). $V=V(\mathbf{r},t)$is the scalar potential, $\...
kalkanistovinko's user avatar
3 votes
2 answers
739 views

Derivation of curl of magnetic field in Griffiths

Can someone please derive how $$\frac{d}{dx} f(x-x') = -\frac{d}{dx'} f(x-x')~?$$ In Griffiths electrodynamics, this is directly mentioned. I'm really confused, can someone elaborate!
Ruchi's user avatar
  • 453
3 votes
3 answers
579 views

How does Kirchhoff's voltage law relate to the spatial derivative of voltage?

I'm reading this libretexts article on the basics of transmission line theory. In it, they include this circuit diagram as a model of a uniform transmission line: They then say that applying ...
Mikayla Eckel Cifrese's user avatar
3 votes
1 answer
1k views

Erratum in Griffith's Introduction to Electrodynamics

Applying the divergence to Eq. $47$, we obtain $$ \mathbf{\nabla} \cdot \mathbf{B} = \frac{\mu_{0}}{4\pi} \int \nabla \cdot \left( \mathbf{J} \times \ \frac{\hat{\mathbf{r}}}{r^2}\right) d\tau^{'}. \...
user avatar
3 votes
2 answers
639 views

The strange character of operator $\nabla$

I was first introduced to the mathematical operation gradient, divergence and curl not in Mathematics but during my studies of Electromagnetism. As you all know learning Maths from a Physics teacher ...
user avatar
3 votes
3 answers
116 views

Finding the vector potential

$$\nabla\times\mathbf{B}=\nabla\times\left(\nabla\times\mathbf{A}\right)=\nabla\left(\nabla\cdot\mathbf{A}\right)-\nabla^2\mathbf{A}=\mu_0\mathbf{J}\tag{5.62}$$ Whenever I try to work this out and ...
Phoooebe's user avatar
  • 220
3 votes
1 answer
92 views

Bianchi identity in EMT [closed]

$ ∇_a∇_b F_{ab} = 0 $ ($F_{ab}$ Faraday tensor in EMT.) proof is given by "To see this, assume a Minkowski spacetime for simplicity and adopt Cartesian coordinates, so that the covariant ...
Thejas's user avatar
  • 81
3 votes
1 answer
454 views

Heaviside-Feynman formula derivation

I want to discuss derivation of Feynman-Heaviside formula. The topic has already been discussed here but I can not put there any question that's why I'm making new post. Deriving Heaviside-Feynman ...
Jarogniew Borkowski's user avatar
3 votes
1 answer
513 views

Gradient in the Frenet-Serret coordinate

I was simply thinking that the gradient in the Frenet-Serret coordinate at a particular point is similar to the gradient in the Cartesian coordinate. I simply assumed that Frenet space is an ...
AFZQ's user avatar
  • 119
3 votes
1 answer
310 views

What's the physical meaning of Curl of Curl of a Vector Field?

The curl of curl of a vector field is, $$\nabla \times (\nabla \times \mathbf{A}) = \nabla (\nabla \cdot \mathbf{A}) - \nabla^2 \mathbf{A}$$ Now, curl means how much a vector field rotates ...
Plague's user avatar
  • 121
3 votes
1 answer
838 views

Vector and Scalar Helmholtz equation

This is closely related to this recent question The vector Helmholtz equation is \begin{align} (\nabla^2 + k^2)\boldsymbol{u} = 0 \end{align} The scalar Helmholtz equation is \begin{align} (\nabla^...
Jagerber48's user avatar
  • 15.2k
3 votes
2 answers
164 views

Differentiability of electric field due to bounded volume charge distribution

In books on electromagnetism, one often sees expressions of Maxwell's equations like $\nabla \cdot \mathbf{E}$ and $\nabla \times \mathbf{E}$. These expressions make sense if $\mathbf{E}$ (which is ...
N.G.Tyson's user avatar
  • 802
3 votes
1 answer
67 views

"Deriving" the covariant derivative

Suppose we are working in scalar QED with Lagrangian $$\mathscr{L} = (D_\mu \phi)(D^\mu \phi)^* - \frac{1}{4}F_{\mu\nu}F^{\mu\nu}.$$ I now want to find the form of the covariant derivative $D_\mu$ ...
Geigercounter's user avatar
3 votes
1 answer
163 views

Laplace-Beltrami operator for a vector field

For a scalar field $\varphi$, the "wave" operator is defined as follows: $$\Box \varphi \equiv g^{ab}\nabla_a\nabla_b~\varphi = \frac{1}{\sqrt{|g|}}\partial_a\left\{\sqrt{|g|}~g^{ab}~\...
newtothis's user avatar
  • 603
3 votes
4 answers
638 views

Derivation of covariant derivative

I'm currently doing Introductory QFT and was confused about the origin of the additional terms in the covariant derivate. My understanding is as follows: If we begin with the Dirac Lagrangian ...
Aidan's user avatar
  • 100
3 votes
0 answers
98 views

Why do we assume electromagnetic fields to be doubly differentiable? [duplicate]

It seems like the identities of curl of gradient, divergence of curl, and the simple derivations of electromagnetic waves from Maxwell equations all rely on the symmetry (interchangeability of their ...
Sidd's user avatar
  • 1,169
2 votes
2 answers
822 views

How does the physical meaning of curl is in agreement with these scenarios?

In the foundation chapters of Electrodynamics I was introduced to concept of curl of a vector field. It was defined as follows $$ \nabla \times \mathbf A = \begin{vmatrix} \hat{i} &...
user avatar
2 votes
2 answers
1k views

Why do we need the curl and divergence on Maxwell equations? [closed]

Is there a particular reason to use curl and divergence on the description of electromagnetic fields? Given boundary conditions, if someone knows the curl and divergence of any field, is it always ...
tnb's user avatar
  • 43
2 votes
1 answer
45 views

Why does linear media produce a $1/2$ factor when using partial derivatives?

Oftentimes in Jackson's text there are certain remarks made about linear media (see pg. 226, ed. 2, for example) and there is often a simplification of partial differentials or variations made. For ...
user143's user avatar
  • 134
2 votes
1 answer
2k views

Derivatives with upper and lower indices

I'm studying classical and quantum field theory, but evaluating derivatives of fields (scalar and/or vector) described with upper and lower indices is somewhat new to me. I'm trying to evaluate $$\...
Libertron's user avatar
  • 187
2 votes
2 answers
4k views

Total time derivative of magnetic vector potential $A$

I am looking at this document, which tries to establish the Lagrangian of the Lorentz force. Everything is fine, but I don't see why: $$\frac{dA_i}{dt}=\frac{\partial A_i}{\partial t}+\frac{\partial ...
student1's user avatar
  • 604
2 votes
1 answer
280 views

Factor before Dirac delta in magnetic dipole field formula

I bumped into this formula for the magnetic induction field generated by a dipole, containing Dirac's delta, while studying hyperfine splitting: $$\textbf{B}(\textbf{r}) = \frac{2}{3}\mu_0 \textbf{m}\...
Salvatore Manfredi D's user avatar
2 votes
1 answer
373 views

Gauge covariant derivative, - how do I get the field?

Suppose I wish to create a gauge covariant derivative from $$ \psi(x)\to e^{ia(x)}\psi(x) $$ I first note that the usual derivate is not covariant: $$ \partial_x(e^{ia(x)}\psi(x))=i(\partial _xa(x))e^{...
Anon21's user avatar
  • 1,558
2 votes
1 answer
215 views

Tensor Differentiation

In the book "Tensors, Relativity and Cosmology" the author derived Maxwell's Equation in covariant form using the EM field tensor Lagrangian $L=-\frac{1}{4}F^{jl}F_{jl}$ (source=0). One of the steps ...
Chern-Simons's user avatar
  • 1,047
2 votes
2 answers
598 views

4-Gradient vector and the Field strength tensor

Need some help evaluating the following 4-gradient, that of the gradient of the field strength tensor $$F^{\mu\nu}= \begin{bmatrix} 0 & -E_x & -E_y & -E_z\\\ E_x & 0 & -...
lastgunslinger's user avatar
2 votes
1 answer
551 views

Equating $\partial_{t_r}$ = $\partial_{t}$ in the retarded potentials?

Im reading Griffiths E/M (4th edition) and came across something I don't understand: Page 446, footnote 8 which reads: "Note that $\frac{\partial }{\partial t_r} = \frac{\partial }{\partial t}$ since ...
Donkey Kong's user avatar
2 votes
3 answers
504 views

About field gradient

I read the term field gradient in most of the article about magnetic field. I search it online but most of the explanation is about the math. I wonder in physics, what the gradient field really mean? ...
user1285419's user avatar
  • 2,383
1 vote
3 answers
824 views

Why is emf equal to the rate of change of magnetic flux?

I don't understand how Faraday figured out that the emf induced when a magnet is moved in a coil would be equal to the rate of change of magnetic flux. Yes, I have that formula drilled in my head like ...
Adil Mohammed's user avatar
1 vote
3 answers
1k views

Field strength tensor in spherical coordinates

I'm getting confused by the change of coordinates when calculating the electromagnetic tensor in spherical coordinates. In particular I know that in cartesian coordinates: $$F_{\mu \nu}=\partial_{\mu}...
Mathew's user avatar
  • 771
1 vote
2 answers
812 views

Reason why dot notation isn't used for time derivatives in Maxwell's equations [closed]

Maxwell's equations seem to be usually written: \begin{align} \nabla \cdot \mathbf{E} &= \rho/\epsilon_0,\\ \nabla \cdot \mathbf{B} &= 0,\\ \nabla \times \mathbf{E} &= -\frac{\partial \...
user avatar
1 vote
2 answers
4k views

Derivative of the magnetic field to the vector potential

So the magnetic field is defined with the vector potential A as: $$\mathbf{B}=\nabla\times\mathbf{A}.$$ How would I calculate the derivative: $$\frac{\delta}{\delta\mathbf{A}}|\mathbf{B}|^2$$ I ...
Nick's user avatar
  • 3,132
1 vote
1 answer
71 views

Meaning of colon symbol $:$ in optics

When I was reading some early days nonlinear optics paper/textbooks (particularly between 1960-1985), I often see expressions such as: $\chi^{(2)}:\textbf{E}\textbf{E}$ or $\nabla\textbf{E}:\partial \...
physstudent11's user avatar
1 vote
1 answer
258 views

Derive interaction lagrangian for KG equation in QED

The free-field KG lagrangian density for complex scalar field is given as $$\hat{\mathcal{L}}_{\text{KG}}=(\partial_\mu\hat{\phi}^\dagger)(\partial^\mu\hat\phi)-m^2\hat{\phi}^\dagger\hat{\phi}$$ By ...
Rescy_'s user avatar
  • 862
1 vote
1 answer
404 views

Difference between covariant derivatives in general relativity and electromagnetism

There are many similarities between the gauging of a $U(1)$ symmetry to obtain the physics of electromagnetism and the gauging of diffeomorphisms to obtain the physics of general relativity. In ...
AnotherShruggingPhysicist's user avatar
1 vote
3 answers
143 views

Passing from curl to vector product

I don't understand how to obtain second equation with first part in the equation $$ \nabla \times \vec A_0 e^{-j \vec k\cdot \vec r} = -j\vec k\times \vec A_0 e^{-j \vec k\cdot \vec r}. $$ Can you ...
sha's user avatar
  • 13
1 vote
1 answer
253 views

Curl of a vector field with two different systems of coordinates

Let $$\mathbf{H} = H_x \mathbf{u}_x + H_y \mathbf{u}_y + H_z \mathbf{u}_z$$ be a vector field whose components are defined with respect to the unit vectors $\mathbf{u}_x$, $\mathbf{u}_y$ and $\...
BowPark's user avatar
  • 777