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Optics is the study of light, and its interaction with matter. It includes topics such as imaging systems, fiber optics, lasers, quantum optics, and more.
1
vote
Why the real image is always inverted while virtual image is always erect?
For a counterexample, for a thin lens:
$$\frac{1}{p'}-\frac{1}{p}=\frac{1}{f'}
\quad\text{with}\quad
\begin{cases}
p=\overline{OA} & \text{object}\\
p'=\overline{OA'} & \text{image}
\end{cases}$$
The …
2
votes
Imaginary part of refractive index = absorption or extinction?
An answer only for the first part of your question:
It's absorption. You can see it more clearly in Poynting's theorem, where you can relate the fact that the refractive index has an imaginary part wi …
3
votes
Accepted
Non-parallel light diffraction
Yes it does. A common version on the double slit experiment is, in fact, the one you describe. You can, for instance, install a narrow hole with the primary light source behind it. This hole will act …
2
votes
Why do birefringence materials have 2 refractive indices?
In a solid, crystal structure, atoms may be arranged in different ways in different directions. When light enters the crystal, you can decompose its electric field alongside those directions, and its …
2
votes
What is the clear difference between interference and diffraction?
Here's, however, how I usually explain this to my students, usually during and after both quantum physics and optics lessons. … In my optics lesson about diffraction grating, I in fact spend most of the time doing interference computations, and not that much diffraction. …
0
votes
Is lens a type of mirror?
Physically speaking, no. However, some formula like Snell's law look a lot alike for lens and mirror, you can switch from one to the other by (formally) changing the sign of the optical index.
Briefly …
7
votes
On the definition of ray (optics) and wavefront of light
Geometric optics defines a light ray, roughly speaking and using modern terms, as the trajectory of a photon as a pure particle, which would be your second definition. … Wave optics has to come up with a different definition, since there's no "particle" photon in this model. …
36
votes
Can you actually stand inside a rainbow? I see people claiming you can
It's impossible to "stand inside a rainbow" because there is no such place.
A rainbow (or, more accurately, a series of rainbows) is the result of multiple reflections from light rays coming from the …
1
vote
Nomenclature for stationary states in the context of wave equations
There is no universal standard for naming those solutions.
For mechanical or electromagnetic waves, a stationary wave is a wave that doesn't travel, typically of the form:
$$s(x,t)=A\cos(kx)\cos(\omeg …
1
vote
Speed of photon
If you're talking about a real experiment, the answer is $c/v_g$, with $v_g$ the group velocity. In some cases $v_g$ may simply be equals to phase velocity, but it's still important to distinguish the …
1
vote
Multi-slit interference
It's a standard calculation that you'll find in any optic book studying diffraction gratings. In a nutshell:
The wave starting from slit number 0 can be written as:
$$s_0(x,t)=Ae^{i(\omega t-kx)}$$
Fr …
1
vote
How does a rainbow show all of its colours?
When light hits the edge of the droplet (from the inside as well as from the outside), it can undergo a reflection as well as a refraction. So there can be several reflections inside the droplet befor …