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20 votes
5 answers
133k views

How to get distance when acceleration is not constant?

I have a background in calculus but don't really know anything about physics. Forgive me if this is a really basic question. The equation for distance of an accelerating object with constant ...
ben's user avatar
  • 1,527
10 votes
3 answers
59k views

How can an object's instantaneous speed be zero and it's instantaneous acceleration be nonzero?

I'm studying for my upcoming physics course and ran across this concept - I'd love an explanation.
anjunatl's user avatar
  • 203
8 votes
3 answers
7k views

Integrating radial free fall in Newtonian gravity [duplicate]

I thought this would be a simple question, but I'm having trouble figuring it out. Not a homework assignment btw. I am a physics student and am just genuinely interested in physics problems involving ...
Kam's user avatar
  • 93
2 votes
1 answer
2k views

Are velocity and acceleration smooth quantities?

My thinking: acceleration corresponds to a force which is instantaneous, so the acceleration of a rigid body can be rather spiky (non-smooth) velocity (angular velocity) describes the ratio of ...
Hello lad's user avatar
  • 123
10 votes
6 answers
3k views

Physical intuition for higher order derivatives

Could somebody give me an intuitive physical interpretation of higher order derivatives (from 2 and so on), that is not related to position - velocity - acceleration - jerk - etc?
user680111's user avatar
0 votes
2 answers
2k views

Tangential acceleration in circular motion?

A lot of my problems have objects moving in circular paths with tangential and normal components of acceleration. If the tangential component is non-zero though, the speed is changing so the radius ...
dfg's user avatar
  • 2,039
24 votes
7 answers
10k views

Can an object *immediately* start moving at a high velocity?

What I mean is, suppose a ball is fired from a cannon. Suppose the ball is moving at 100 m/s in the first second. Would the ball have started from 1m/s to 2m/s and gradually arrived at 100m/s? And is ...
Siddharth Jossy's user avatar
16 votes
3 answers
3k views

How does anything move? [duplicate]

So in order for two things $A$ and $B$ to move apart, for example, relative to each other, $B$ can be set into motion away from $A$. This means that we have to increase $B$'s velocity and therefore ...
under_the_sea_salad's user avatar
9 votes
5 answers
8k views

Is there a scalar acceleration?

The magnitude of Velocity is simply Speed. On the other hand, the magnitude of Displacement seems to be a simpler idea than Distance. And the magnitude of Acceleration is not the change of Speed over ...
clausvalca226's user avatar
25 votes
7 answers
12k views

Zero velocity, zero acceleration?

In one dimension, the acceleration of a particle can be written as: $$a = \frac{dv}{dt} = \frac{dv}{dx} \frac{dx}{dt} = v \frac{dv}{dx}$$ Does this equation imply that if: $$v = 0$$ Then, $$\...
7453rfg's user avatar
  • 393
17 votes
5 answers
6k views

Velocity is to speed as acceleration is to ________? [duplicate]

Vectors give both magnitude and direction, whereas scalars can be thought of as magnitude without direction. So, velocity is a vector since it is speed with direction. Similarly, what is the scalar ...
user avatar
2 votes
9 answers
111k views

Why isn't the acceleration at the top point of a ball’s journey zero?

When I shoot a ball vertically upward, its velocity is decreasing since there is a downward acceleration of about $9.8\,\mathrm{ms}^{-2}$. I have read that at the top most point, when $v = 0$, the ...
Aaryan Dewan's user avatar
  • 1,790
0 votes
5 answers
16k views

tangential acceleration for uniform circular motion

I understand that circular motion is defined by 2 components of acceleration, one tangential and one radial and their resultant is what causes circular motion. I am confused though as to why it is ...
SoHCahToha's user avatar
6 votes
10 answers
291k views

What does the magnitude of the acceleration mean?

I am a little confused as to what the magnitude of acceleration is and what it means.
user40230's user avatar
2 votes
1 answer
9k views

Kinematics with non constant acceleration

A particle experiences an acceleration described by $$ a=kx^{-2} $$ where x is the displacement from the origin and k is an arbitrary constant. To what value does the velocity v of the particle ...
Andrew Liu's user avatar
1 vote
1 answer
113 views

What will be the trajectory of the given motion [closed]

If it is given that component of acceleration perpendicular to the velocity of a body has a constant, non-zero magnitude, how can we mathematically prove that the trajectory of the body will be ...
Aumkaar Pranav's user avatar
1 vote
7 answers
293 views

I'm having trouble understanding the intuition behind why $a(x) = v\frac{\mathrm{d}v}{\mathrm{d}x}$ [duplicate]

I was shown \begin{align} a(x) &= \frac{\mathrm{d}v}{\mathrm{d}t}\\ &= \frac{\mathrm{d}v}{\mathrm{d}x}\underbrace{\frac{\mathrm{d}x}{\mathrm{d}t}}_{v}\\ &= v\frac{\mathrm{d}v}{\mathrm{d}x} ...
Kalcifer's user avatar
  • 339
16 votes
5 answers
3k views

What is the best path for a given initial and final state?

I am trying to calculate an efficient acceleration curve given starting and final positions and velocities. I'm assuming no friction, and that the acceleration can be applied in any direction at any ...
generesque's user avatar
15 votes
4 answers
396 views

Problems in the relation $a=v\frac{\mathrm{d}v}{\mathrm{d}x}$

We all know $a = \frac{\mathrm{d}v}{\mathrm{d}t}$. A little application of the chain rule leads to the relation $$a=v\frac{\mathrm{d}v}{\mathrm{d}x}$$ But the above equation shows that $a=0$ whenever $...
Prashant Singh's user avatar
14 votes
4 answers
2k views

Why doesn't constant acceleration give me total displacement?

I started learning 1D kinematics and learnt definitions of constant velocity and constant acceleration. I thought that if a particle is changing its velocity uniformly then it has constant ...
Sai Varun 's user avatar
9 votes
2 answers
2k views

Non-Constant Acceleration due to Gravity

Recently, I had the first physics lab for my university physics course. This lab was fairly simple, as we were merely using a computer and a distance sensor to graph the position, velocity, and ...
mfabel's user avatar
  • 93
6 votes
4 answers
838 views

How can I write the vector form of this equation, $a = vdv/dx$?

My Physics teacher was deriving the 'Work-Energy Theorem' for a single particle in the class; where after doing the vector addition of all the forces acting on the particle, he put the resultant of ...
Juhi Kumari's user avatar
4 votes
1 answer
258 views

Special Relativity and Accelerated Reference Frames

I am looking for a good reference on how to treat accelerating reference frames in special relativity, particularly with respect to accelerating linear motion and circular motion. Are there any that ...
3 votes
2 answers
43k views

Difference between Speed and Velocity

What is the difference between Speed, Velocity and Acceleration? Could any one describe it pictorially?. I am more over confused even after investigating many times. I am unable to relate myself ...
ddpd's user avatar
  • 133
3 votes
2 answers
312 views

Motion with constant speed and constant acceleration magnitude

I was reading this and this posts. From what I gather In 2D: Constant speed $||\dot x||=const$ and constant positive magnitude of the acceleration $||\ddot x|| = const$ imply circular motion. In 3D: ...
Euler_Salter's user avatar
2 votes
2 answers
15k views

Why can velocity and acceleration be negative?

Why is speed and acceleration negative when $V_1$ of an object is say 150m/s, $V_2$ is 0 m/s and $\Delta d=0.50\,\rm m$? I found the time it takes which is 0.0033s and the acceleration to be 90909.09 ...
Bethany's user avatar
  • 21
2 votes
4 answers
8k views

How is acceleration measured if there is change only in the direction of velocity & not magnitude?

The formal definition of acceleration is It is the measure of how fast the velocity changes with respect to time. Now, when the magnitude of velocity changes, acceleration $$\vec{a} = \frac{d \...
user avatar
1 vote
3 answers
2k views

Difference between different radial and centripetal accelerations:(Doubt)

In cylindrical coordinates I had derived the acceleration as : for the first component of acceleration, what is the difference between radial and centripetal ?
Prakul Virdi's user avatar
1 vote
3 answers
2k views

How to approximate acceleration from a trajectory's coordinates?

If I only know $x$- and $y$- coordinates of every point on a trajectory without knowledge of time information, is there any way to approximate Cartesian acceleration angle at each point? Time interval ...
sgyf's user avatar
  • 43
1 vote
1 answer
12k views

What is the difference between negative acceleration and decreasing acceleration?

According to Reisnick and Halliday, retardation is the acceleration in the negative direction of time axis ie. opposite to the motion. Decreasing accleretion is the decrease in the magnitude of time ...
user avatar
1 vote
4 answers
25k views

Deriving equations of motion using integration

Please refer to my school textbook pg48 (of the book, and not the pdf counter) here: http://ncertbooks.prashanthellina.com/class_11.Physics.PhysicsPartI/ch-3.pdf My doubt is in this context: (right ...
Saurabh Raje's user avatar
  • 1,138
1 vote
2 answers
3k views

In 1D why are vectors, such as, e.g., velocity $v$ and acceleration $a$, not written with a vector arrow?

In my textbook instantaneous velocity and acceleration are wrote only as $v$ and $a$ in the chapter of One dimensional motion. Instead, in two dimensional motion chapter they are written with the "...
Antonio Logarzo's user avatar
1 vote
3 answers
88k views

How to find stopping distance of a car? [closed]

I am trying to calculate the minimum stopping distance of a car once the brakes are applied. I know that $F = ma$, and the braking force is $F = \mu N = \mu m g$, so $$a = \mu g.$$ Next, by applying ...
Gauzi's user avatar
  • 19
0 votes
4 answers
672 views

Question about $a = v\ \mathrm dv/\mathrm dx$

Consider $\vec{v}$ Now differentiating this w.r.t time, $$\vec{a} = d/dt( \vec{v}) = \vec{v}(d\vec{v}/dx)$$ Now this multiplication of vectors obviously makes no sense. This along with the fact that ...
xasthor's user avatar
  • 1,106
20 votes
5 answers
6k views

Why do these two ways of understanding constant acceleration give different results?

I have a question pertaining to the concept of acceleration and it's formula - Both seem to give me different answers. I was asked: A train is moving at a velocity of $20\ \mathrm{m/s}$. It hits ...
Priyank 's user avatar
15 votes
5 answers
8k views

How to brake 'beautifully'?

Sometimes when I'm driving my car, I play a "game" against myself in which I try to minimize the deceleration felt by passengers (including myself) while still braking in a reasonable short space. I ...
Alpha's user avatar
  • 253
13 votes
4 answers
3k views

What would qualify as a deceleration rather than an acceleration if speed is unchanged?

The instantaneous acceleration $\textbf{a}(t)$ of a particle is defined as the rate of change of its instantaneous velocity $\textbf{v}(t)$: $$\textbf{a}(t)=\frac{\mathrm{d}}{\mathrm{d}t}\textbf{v}(t)....
SRS's user avatar
  • 27.2k
13 votes
7 answers
3k views

Can we divide a vector by another vector? How about this: $a = vdv/dx?$

My physics teacher told us that we can’t divide vectors, that vector division has no physical meaning or significance. How about this: $$a = vdv/dx.$$ It says acceleration vector equals velocity (as ...
4d_'s user avatar
  • 876
7 votes
2 answers
25k views

How to remove gravity component from accelerometer $X$, $Y$ readings?

So I have an accelerometer which I am wanting to use in an IMU. When the device is tilted but stationary I want the x, y values to be 0, so effectively negate the effect of gravity along the x and y ...
Adam's user avatar
  • 173
6 votes
5 answers
77k views

If an object moved 5 meters in a second, how can its velocity be 10 m/s? [duplicate]

On physicsclassroom.com, an assignment gives data for an object experiencing acceleration: This is the corresponding chart for the object's velocity: At $0$ seconds the position of the object is $0$...
user2620463's user avatar
6 votes
2 answers
1k views

Terminology for time derivative of speed (not velocity)

Is there any standard terminology for the derivative of the magnitude of velocity with respect to time (suitable for use in first-year Calculus)? The word ‘acceleration’, in its technical sense, is ...
Toby Bartels's user avatar
5 votes
2 answers
330 views

How long does it take to optimally change position and velocity?

A spaceship moving in two dimensions is at position $(x, y)$ and has a velocity $(v_x, v_y)$. It also has a maximum acceleration $a_{max}$. Its goal is to be at position $(x', y')$ with a velocity of $...
Matthew Piziak's user avatar
5 votes
4 answers
2k views

Is there any such thing as a change in acceleration (ex: 3 m/s/s/s)? [duplicate]

If there exists something like that, then in $distance/time/time/time$, how is it expressed?
Amit Amola's user avatar
4 votes
3 answers
794 views

Why is harder to accelerate object at higher speeds if speed is relative term?

Why is it harder to accelerate object at higher speeds (even if resistance forces dont exist) if speed is a relative term? Object speed is relative term, it depends from wich frame of reference we are ...
22flower's user avatar
  • 730
4 votes
2 answers
4k views

Formulas for ball rolling in a bowl?

I'm developing a program where I've a ball/sphere rolling in a bowl from the side at top, till the center at bottom, and I'm trying to get the formulas for: The rotation angle and the position of the ...
Dane411's user avatar
  • 141
3 votes
5 answers
2k views

Instantaneous acceleration vector toward the concave side of a curved path

Why does the instantaneous acceleration vector of a moving particle always point toward the concave side of a curved path? My college textbooks mention this as something obvious, without further ...
Berni's user avatar
  • 33
3 votes
4 answers
2k views

In perfect vacuum (no external force), if I apply a small amount of force to a body, will it continue to accelerate forever?

According to the equation $F = ma$, the greater the force applied to a body, the greater its acceleration. But in a place where there is no gravity or any other kind of external force, if I apply a ...
anonymous's user avatar
  • 227
3 votes
1 answer
1k views

Confusion in coordinate transformation of acceleration vector

Consider this notation for vectors: $A_{cb}^{d}$ is the $A$ vector (velocity,acceleration, angular velocity or ...) of $b$ coordinate frame w.r.t. $c$ frame presented in $d$ frame axis. I know when we ...
danielRS's user avatar
3 votes
4 answers
9k views

What is the difference between uniform velocity and constant velocity? [closed]

I think that uniform velocity implies constant speed but not constant direction. while constant velocity implies constant speed without any changes in direction. Both tell us that there's no ...
GOGA's user avatar
  • 41
3 votes
2 answers
2k views

Utilizing maximum acceleration $a$ for displacement $d$ with initial velocity $v_0$ and final velocity $v_1$

Problem My goal is to move an object from point a to b (displacement $d$) as fast as possible utilizing the maximum available acceleration $a_{max}$, taking into account the initial velocity $v_0$ ...
Jonathan Persson's user avatar