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Questions tagged [velocity]

The time rate of change of the position of an object

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2 objects moving towards a midpoint near light speed [on hold]

I have the following diagram (velocities are relative to p2): and I have the following line of reasoning: The speed of P2 relative to P1 is also 0.9c Therefore P1 experiences 2 seconds of time ...
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Oil droplet in Electric field [on hold]

suppose a horizontal plate capacitor. They are separated by $d=0.005 \text{m}$. In a homogeneous field, the oil droplet ($m=3\cdot 10^{-15} \text{ kg}$) sits at the bottom of the lower plate. Like a ...
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Acceleration of a satellite orbiting Mars

I am studying how a satellite would move in orbit around Mars. I have calculated the velocity of its movement. However, if the gravity of Mars is the only force affecting the movement of the satellite,...
22 views

How to find the ideal intersection between constant object and controllable object?

So I'm an engineer who's a bit out of practice, but have taken up a side project for entertainment purposes. I'm trying to teach myself to code and find myself struggling to come up with a solution ...
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Is it possible to find the exact value of the dynamic viscosity of a fluid by applying Stokes' law?

I am a high school student who is investigating the dynamic viscosity of a fluid. Typically, high school physics model the dropping of a spherical object vertically into a viscous fluid with the ...
136 views

Calculating mean velocity: using time or velocity? [closed]

Background I have been running tests which involve timing an object moving a certain (fixed) distance, $s$. Each test has been repeated 3 times, and the 3 times ($t{_{1}}, t{_{2}}, t{_{3}}$) for the ...
115 views

Can the flow be irrotational if the viscous forces act on fluid?

I tried to answer the question only using the definitions and the Navier-Stokes equation: $$\rho \frac{Dv}{Dt} = -\nabla P +\rho g -\mu[\nabla \times(\nabla \times v)]$$ In my opinion if the ...
In non-relativistic physics, physical quantities $Q$ are characterized by how they transform under a Galilean transformation $g \in \mathcal{G}$. $$Q \rightarrow Q' = D[g]Q$$ where $D[g]$ is the ...