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Use of $dv/ds$ in defining acceleration [duplicate]

We can write acceleration as either $dv/dt$ or $v dv/ds$. And surprisingly the work-energy theorem arrives from the second definition. I feel it would be fundamentally understanding towards work ...
Psychic456's user avatar
26 votes
21 answers
5k views

What happens when a car starts moving? The last moment the car is at rest versus the first moment the car moves

Imagine a car that's at rest and then it starts moving. Consider these two moments: The last moment the car is at rest. The first moment the car moves. The question is: what happens between these 2 ...
fab's user avatar
  • 371
1 vote
1 answer
481 views

Doubt in Verlet's Algorithm

In studying the temporal evolution of a system according to the deterministic model, we begin by considering a Taylor series expansion for the displacement $r$. First, we consider a positive variation ...
user3204810's user avatar
0 votes
1 answer
90 views

Derivative of the product of a scalar function and a vector valued function

According to Berkeley Physics Course, Volume 1 Mechanics, The time derivative of a vector valued function can be derived from the formula: $$ \mathbf{r}(t) = r(t)\mathbf{\hat{r}}(t) $$ where the ...
coolguy79's user avatar
2 votes
1 answer
247 views

How to calculate jerk in uniform circular motion?

We can calculate the centripetal acceleration in circular motion by the equation v^2/r. But how do we calculate the jerk (which is acceleration over time)?
Carl's user avatar
  • 23
1 vote
1 answer
76 views

How do force and mass work with all derivatives of position?

I think if $F(t) = kt^0$ then $$x(t) = x_0 + v_0t + \frac{k}{m}\frac{t^2}{2!},$$ and if $F(t) = kt^1$ then $$x(t) = x_0 + v_0t + \frac{k}{m} \frac{t^2}{2!} + \frac{k}{m} \frac{t^3}{3!},$$ and so on, ...
clara raquel's user avatar
0 votes
7 answers
104 views

How does the result of derivative become different from average ratio calculation?

Lets give an example. Velocity, $v=ds/dt$. If we know the value of $s$ (displacement) and $t$ (time), we can instantly find the value of $v$. But then this $v$ will be the average velocity. Now ...
Arafat's user avatar
  • 15
-1 votes
2 answers
80 views

Problem with resources, Walter Lewin's third lecture

I've watched Walter's third lecture in 8.01 and I have a small problem with the last part, where he says that $$\vec r_t=x_t\cdot \hat x\ +\ y_t\cdot \hat y\ +\ z_t\cdot \hat z \\ \vec v_t=\frac{d\vec ...
0 votes
1 answer
89 views

In $a = dv/dt$, is $a$ the net acceleration? [closed]

While going through the calculus approach to accelerate, we have, $$a = dv/dt, $$ I think, here, v and a should be in the same axis, is my process correct? in a planar motion in two dimensions, it ...
sachin's user avatar
  • 1
1 vote
2 answers
142 views

Average velocity showing different results

I was solving a question, in which, a particle has travelled a distance $s$, with initial velocity $0$ and constant acceleration. So the equation of motion becomes, $$ v = a t \tag{1} $$ and $$ v = \...
Agent_A's user avatar
  • 56
-2 votes
3 answers
96 views

Why is it wrong to find centripetal acceleration using change of velocity over change of time?

This question asks to find the centripetal acceleration by giving the initial and final velocity over the change of time. As shown, my book combined two rules to find the acceleration. I utterly ...
Manar's user avatar
  • 377
0 votes
2 answers
42 views

Velocity to Acceleration negative line [closed]

Is the velocity line in below 0 is a different acceleration line? For example from 0 - 6s and from 10 - 17s. It has the same slope.
Howard Tran's user avatar
-2 votes
2 answers
122 views

Why does $\vec{a}=\vec{\omega}\times \vec{r}$ as well as the velocity does?

Today I came in class and in one of the problems the teacher used $\vec{a}=\vec{\omega}\times \vec{r}$ which made me very confused because I don't know where it comes from, it seems pulled out of thin ...
Ulshy's user avatar
  • 69
-1 votes
1 answer
164 views

Given a Postion-time curve/function, how do I find the time spent per unit position?

I have recordings of the position time curve for a given 1D actuator. I'm trying to find out the time spent per unit length. To get this relationship, I tried to take an example of a linear function: $...
BikerDude's user avatar
1 vote
3 answers
233 views

Problem with the constant magnitude of vectors if the change in the same vector is perpendicular to it [duplicate]

Note: I am merely a highschool student attempting to self-study Classical Mechanics, some of the assumptions I make are perhaps wrong, so please bear with me. Thank you. This while can be condensed ...
Adyansh Mishra's user avatar
2 votes
4 answers
261 views

Show that $d\mathbf{v}^2/dt = 2\mathbf{v}\cdot d\mathbf{v}/dt$ using geometry only

I have just begun reading Modern Classical Physics by Thorne and Blandford and I am trying to wrap my head around their "geometric viewpoint" on classical mechanics. The first exercise in ...
Nic Christopher's user avatar
2 votes
3 answers
198 views

What is the definition of velocity?

We know that displacement is change in an object's position (here position means 'position vector'). Then velocity will be change in position of the object with respect to time, simply displacement/...
Priyanshu Chauhan's user avatar
0 votes
3 answers
82 views

Chain rule when the intermediary variable might be equal to zero

I came across the following question in the kinematics section of my introductory physics textbook: The velocity of a particle moving along x-axis is given as $v=x^2-5x+4$ (in $m/s$), where $x$ ...
Arham Jain's user avatar
0 votes
0 answers
45 views

Physical and Diagrammatic representation of $a$=undefined when $v$=0 according to $a$=$vdv$/$dx$

$a$=acceleration $v$=velocity $x$=position along x axis $t$=time instant My teacher derived the $a$=$v$$dv$/$dx$ formula as follows Assume a particle at time $t$ is at $x$ position having $v$ velocity ...
Rita Garain's user avatar
0 votes
2 answers
414 views

Why does tangential acceleration become 0 when the velocity is max? [closed]

I know that tangential acceleration equal to zero when the circular motion is uniform, but why is it equal to zero, when the velocity is max or min? Because there is no relation between the value of ...
Alia's user avatar
  • 11
0 votes
1 answer
43 views

Are terms tangential acceleration and normal acceleration only used for instantaneous velocity?

Are terms tangential acceleration and normal acceleration only used for instantaneous velocity?
Naman Singh's user avatar
4 votes
6 answers
855 views

How to understand instantaneous velocity concept [duplicate]

When I started learning instantaneous velocity it didn't make sense to me. I don't understand in real life why we can't measure instantaneous velocity and therefore why we use this concept. Or is this ...
Heroz's user avatar
  • 311
-1 votes
2 answers
67 views

Instantanous and uniform velocity and acceleration [closed]

If the mathemical expression of instantanous velocity is $d/t$, what is the mathematical expression of uniform velocity. If the mathematical expression of instantanous acceleration is $v/t$, what is ...
Meta_Alchemy's user avatar
2 votes
1 answer
172 views

How does instantaneous velocity cause displacement in just one point? [closed]

I have a question. Falling object graph is curve shape right? And instantaneous velocity is tangent line but how does this velocity make displacement in distance? Because suppose instantaneous ...
Heroz's user avatar
  • 311
1 vote
0 answers
93 views

Does car move when instantaneous velocity is zero? [duplicate]

In 3blue1brown: derivative paradox. supposed car moving with: $S(t) = t^3$ And velocity is: $V(t) = 3t^2$ He asked when t = 0 velocity is 0 m/s , does that car move at that time ? And here his ...
Heroz's user avatar
  • 311
0 votes
1 answer
73 views

Why did my rearrangement with chain rule end up equating velocity to position?

We all know acceleration is the time-derivative of velocity which in turn is the time-derivative of position. Vice versa: position is the integration of velocity and velocity itself is the integration ...
KMC's user avatar
  • 401
1 vote
7 answers
293 views

I'm having trouble understanding the intuition behind why $a(x) = v\frac{\mathrm{d}v}{\mathrm{d}x}$ [duplicate]

I was shown \begin{align} a(x) &= \frac{\mathrm{d}v}{\mathrm{d}t}\\ &= \frac{\mathrm{d}v}{\mathrm{d}x}\underbrace{\frac{\mathrm{d}x}{\mathrm{d}t}}_{v}\\ &= v\frac{\mathrm{d}v}{\mathrm{d}x} ...
Kalcifer's user avatar
  • 339
1 vote
3 answers
95 views

What is the rate of change of time wrt velocity of an object?

disclaimer, I'm just an average highschooler so please be a little friendly with the mathematics of your answers but I wondered what would be $dt/dv$?
Sciencenium's user avatar
0 votes
1 answer
742 views

What are the relationships between the motion-time graphs?

I was wondering if someone could explain the relationships between the three motion graphs (Position-Time, Velocity-Time, and Acceleration-Time). I believe that the slope of the P-T is Velocity and ...
Enrageder's user avatar
0 votes
1 answer
87 views

How do I reconcile these two definitions of acceleration?

How do I reconcile these two definitions of acceleration? $$a=\frac{d\bar{v}}{dt}=(\frac{dv^k}{dt}+v^i v^j \Gamma^k_{ij})\bar{e}_k \tag{1}$$ and $$a^k=v^{\small\beta} \nabla_{\small\beta} v^k.\tag{2}$$...
jelly ears's user avatar
3 votes
2 answers
160 views

Acceleration in terms of displacement

I am having problems understanding the derivation of acceleration in terms of displacement. The first step is fine: $$a(x) = \frac{\mathrm dv(x)}{\mathrm dt} = \frac{\mathrm dv(x)}{\mathrm dx} \frac{\...
Hugo Lundin's user avatar
2 votes
1 answer
435 views

When exactly does velocity increase or decrease on an acceleration time graph? [closed]

How does the acceleration time graph show if and object is speeding up or slowing down? Is it possible to find the answer without any deep calculations? If yes then how? Like how can I find the ...
Aarya Chavan's user avatar
-4 votes
1 answer
97 views

Differentiation [closed]

Why is $$\frac{d}{dt}v^2=2v\frac{dv}{dt},$$ When: $$\frac{d}{dx}x^2=2x,$$ where $v$ is velocity? I don't understand why the variable $x^2$ has the derivative of $2x$, whereas the variable velocity has ...
Franz Liszt's user avatar
0 votes
4 answers
127 views

Standing Wave Equation: Why does assuming a small slope $du/dx$ not make $d^2u/dx^2$ negligible as well?

Referencing the above image, just change the label for $y$-axis to $u$-axis.^ Following the derivation of the standing wave equation: https://www.youtube.com/watch?v=IAut5Y-Ns7g&t=1324s So if ...
Dutonic's user avatar
  • 719
1 vote
1 answer
94 views

Simple difference between module of velocity and time derivative of module of position [duplicate]

What is the conceptually difference between the two: $$\frac{d|\vec{r}|}{dt}=\frac{\vec{r}\cdot\frac{d\vec{r}}{dt}}{|\vec{r}|}\neq|\dot{\vec{r}}|\equiv \bigg|\frac{d\vec{r}}{dt}\bigg|$$ ...
Acephalus's user avatar
  • 189
10 votes
7 answers
1k views

What is the instant velocity? [duplicate]

The velocity is the variation rate of the position correct? So does it make sense to talk about velocity without time?
Lipe5421's user avatar
  • 117
0 votes
2 answers
353 views

Why isn't tangential acceleration just always 0?

This is probably a very stupid question but I can't help me. Tangential acceleration is $\vec{a_t}=\frac{dv}{dt}\frac{\vec{v}}{v}=\frac{\vec{v} \cdot \vec{a}}{v} \frac{\vec{v}}{v}$. Since $\vec{a}$ is ...
Quaeram's user avatar
  • 15
0 votes
1 answer
129 views

Why intuitively is the tangent vector the derivative of velocity of position with respect to their modulus?

When trying to find the tangential velocity, many textbooks define the tangent direction as one of the following: or Intuitively, why is the tangent vector the derivative of the position with ...
XXb8's user avatar
  • 849
0 votes
1 answer
42 views

Is such a situation realistically possible where $v$-$t$ graph is continuous but $a$-$t$ graph is not?

Taking for example $v = \cos(t-1)$ from $t \in [0,1]$ and $v = e^{t-1}$ from $t \in (1,\infty)$ and $t \ge 0$. At $t = 1$, the function shifts from cosine to exponential, but remains continuous since ...
Hoor Tiku's user avatar
1 vote
3 answers
307 views

What does the derivative of unit vector of velocity with respect to time represent?

let an object move with a constant accelration a. in my book,the following derivatve is said to be non-constant(variable). $$\frac{d[\frac{v}{|v|}]}{dt}$$ what does this mean? as far as i can think,it ...
Karan's user avatar
  • 41
3 votes
3 answers
296 views

If the displacement of an object is not differentiable at some point, say $x(t)=t\sin(1/t)$ at $t=0$, how is its instant $v$ defined? [closed]

If instant velocity at any given time $t_0$ is defined as the derivative of $x(t)$ at $t_0$, what if the derivative does not exist? How are we supposed to deal with $x(t)=|t|$ at $t=0$, or for more ...
barbatos233's user avatar
3 votes
2 answers
233 views

Generalization of straight line motion under constant acceleration

My question is that, we all know the three equations of straight line motion under constant acceleration, \begin{align} x & =x_{\rm o}+v_{\rm o}\,t+\tfrac12 \mathrm a\,t^2 \tag{1d-a}\label{1d-a}\\ ...
Sohaib Ali Alburihy's user avatar
1 vote
1 answer
459 views

Expressing acceleration in terms of velocity and derivative of velocity with respect to position

we know that $$a = \dfrac{dv}{dt}$$ dividing numerator and denominator by $dx$, we get $$a=v\dfrac{dv}{dx}$$ provided that $dx$ is not equal to zero or instantaneous velocity not equal to zero when I ...
Lalit Tolani's user avatar
2 votes
3 answers
131 views

Is motion in infinitesimal interval is linear?

As a kind of thought experiment I tried to think if a motion (including circular motion), when divided into infinitesimal time intervals is always linear motion (whether each interval of the motion is ...
Idop11's user avatar
  • 121
-4 votes
1 answer
71 views

Given that $m \dot v \cdot v = 0$ , how is it equal to $m \frac{d}{dt} (v \cdot v)/2$? [closed]

While studying about scalar triple product in vector algebra, I stumbled upon the following question with the solution. I want know how is $m \dot v \cdot v $ = $m \frac{d}{dt} (v \cdot v)/2$?
Adi Anil's user avatar
0 votes
1 answer
78 views

Particle paths - the distance moved by a particle in a velocity field

This question is is context to particle paths. Particle paths are trajectories of a given particle in the velocity field: $$\boldsymbol{u}(\boldsymbol{x},t)$$ A particle location at position $\...
Jack Jack's user avatar
  • 187
2 votes
1 answer
292 views

Is the relation "slope=velocity" mathematically valid?

$\text{Slope= tan(angle with respect to positive X-axis)= scalar output}$ $\text{velocity= a vector }$ Source: Hugh D Young_ Roger A Freedman - University Physics with Modern Physics In SI Units (...
Sahil's user avatar
  • 439
2 votes
1 answer
267 views

Is there a difference between instantaneous speed and the magnitude of instantaneous velocity?

Consider a particle that moves around the coordinate grid. After $t$ seconds, it has the position $$ S(t)=(\cos t, \sin t) \quad 0 \leq t \leq \pi/2 \, . $$ The particle traces a quarter arc of ...
Joe's user avatar
  • 131
3 votes
2 answers
133 views

Is this notation inconsistent? If not, can some explain why not?

Im working through a textbook section on particle kinematics. An example given is relating vertical velocity to horizontal velocity and states: $y$ has a constant velocity of $10 \ \rm [m/s]$ $y=(0....
RoRo's user avatar
  • 31
0 votes
2 answers
71 views

Why quantities in physics are always talking about rates? [closed]

I get the idea that physics wishes to study changes to discover new rules. But why is everything related to rates? Acceleration,Velocity? Could we use something else apart from these? What can you ...
Shadman Sakib's user avatar