0
$\begingroup$

Is the velocity line in below 0 is a different acceleration line?

For example from 0 - 6s and from 10 - 17s. It has the same slope.

enter image description here

$\endgroup$
2
  • 1
    $\begingroup$ It has the same slope. One has negative slope and the other positive slope, so they aren’t “the same slope”. $\endgroup$
    – Ghoster
    Commented Sep 22, 2023 at 18:37
  • $\begingroup$ The question is a bit unclear. Would you be able to adjust the description? $\endgroup$
    – Steeven
    Commented Sep 22, 2023 at 18:39

2 Answers 2

0
$\begingroup$

I am not sure what you mean by velocity line or acceleration line, but they do have the same magnitude of slope but different signs. The slope from 0-6 is negative 1 and from 10-17 positive 1. And if the graph above were a velocity vs time graph, the slope would represent the acceleration and the acceleration line which would be on acceleration vs time graph would be a horizontal line at -1 for zero to six and 1 from 6 to 10. And the slope from 6 to 10 is zero and so there is no acceleration.

$\endgroup$
0
$\begingroup$

Up to t=6s the accelleration is -1m/s^2 if time scle is s and v scale is m/s. From 6s to 10s a=0 and fro, 10s to 17d accelleration is +1m/s^2

$\endgroup$

Not the answer you're looking for? Browse other questions tagged or ask your own question.