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12 votes

Why are spectrums of incandescent light bulbs continuous despite the presence of Argon around them?

Seeing thin absorption lines is difficult. You need pretty good equipment to see them over an extended body. If you're just looking at it with a prism, it will overlap enough that such lines are ...
BowlOfRed's user avatar
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3 votes

What is the difference between the dipole in IR and Raman vibrations?

Both IR absorption/Rayleigh scattering and Raman scattering involve oscillating electric moment of molecules. But just because there is Raman scattering, and therefore electric moment oscillates, it ...
Ján Lalinský's user avatar
2 votes

Decoding the character table

Looking at page 81 and 82 of Applications of Group Theory To the Physics of Solids. by A. Dresselhaus it seems that the second last column are the possible basis functions of that irreducible ...
Martin Ueding's user avatar
2 votes
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Baseline correction algorithm for Raman spectra. Raman baseline removal

For each abscissa, read off the numerical values for the ordinates of the two plots and pair them - the first value from your spectrum as $x$ and the value from the P Cygni data as $y$. Now load ...
Selene Routley's user avatar
2 votes

Lorentz distribution in emission peaks

The Lorentzian line shape arises when the width of the peak is determined by homogeneous broadening. It isn't an arbitrary choice by overzealous curve fitters, that really is the expected shape of the ...
John Rennie's user avatar
2 votes
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Classical treatment of Raman effect

In this basic classical treatment, you will always get Raman scattering, whether you send in a modulated or DC field. But in reality, all of the details come from the innocuous-looking "oscillator ...
Gilbert's user avatar
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2 votes
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How does Raman scattering not break energy quantization?

Like any good quantum mechanical phenomenon, Raman scattering admits both a wave picture and a particle picture. You might not like either of them, though. As far as the photon picture goes, it's ...
Emilio Pisanty's user avatar
2 votes
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Laser flux power density and Raman scattered radiation

Well, sorry for the short answer, but "laser flux power density" is just $I_0$, which is the power per unit surface area (which is why it is called flux power density) and the Raman intensity is ...
Ofek Gillon's user avatar
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2 votes

The typical IR spectrometer broadband source emits all IR frequencies of interest simultaneously

There are two possible routes to making a broadband light source. Incoherent sources The first way is to make a source that emits light at a bunch of different frequencies without any coherence ...
Emilio Pisanty's user avatar
2 votes
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The typical IR spectrometer broadband source emits all IR frequencies of interest simultaneously

Thermal emission (often idealized as blackbody radiation) is broadband, i.e. emitting multiple frequencies at once. An incandescent lightbulb is like this. The references provided in the question make ...
kleingordon's user avatar
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2 votes
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Complex dielectric function and normal reflectance

Let me take you through deriving the boundary conditions. I had a fantastic Prof, who explained this very well. We can derive them by evaluating some of Maxwell's equations at the interface. ...
Samalama's user avatar
  • 511
2 votes
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How to determine if a calculated Raman mode in a crystal is active or not?

In principle you should determine the irreducible representation of the mode, i.e. how its eigenvector transforms under the symmetry operation of the space group, and look up whether the irreducible ...
Jannick's user avatar
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2 votes
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Are virtual states eigenstates of physical observables?

The wikipedia page called "virtual state" is too brief to be useful. The problem is that it does not ever define what it means by a virtual state. I think the term "virtual state" ...
Andrew Steane's user avatar
1 vote
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450nm peak absorption

Try cerium doped scintillation crystals made from gadolinium aluminum gallium garnet, see https://www.nature.com/articles/s41598-020-77451-x. In metal oxides, the valence band is primarily composed of ...
secr's user avatar
  • 215
1 vote

Real part of Raman response function in linear response theory?

This can be understood on general grounds through the theory of linear response. In Raman scattering and many other cases, we're typically interested in the response of a Hermitian operator to a real-...
Anyon's user avatar
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1 vote
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Raman scattering collection geometry

I will answer this question from the perspective of the Raman scattering experimentalist with the condensed matter background. These are, indeed, most popular geometries with backscattering one being ...
Mr.Eight's user avatar
1 vote

What's the difference between inelastic X-rays scattering and Raman scattering?

Raman Scattering is indeed an inelastic scattering process. Raman scattering is synonymous to inelastic scattering of photons. Raman scattering is usually done in IR region, the reason being ...
TheImperfectCrazy's user avatar
1 vote

Why are spectrums of incandescent light bulbs continuous despite the presence of Argon around them?

For the argon inside a light bulb to affect the passage of light through it in a measurable way, it needs to be hot enough to be ionized. Then it will begin absorbing and emitting its characteristic ...
niels nielsen's user avatar
1 vote

Why are spectrums of incandescent light bulbs continuous despite the presence of Argon around them?

Sure, argon absorbs some light at its favorite wavelengths. It probably does create some tiny dips in the lamp spectrum - and off my head I am sure there is no that much precise measurement technique ...
fraxinus's user avatar
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1 vote

How to explain about Raman spectroscopy?

Raman spectroscopy is an instance of inelastic scattering of light by molecules in the lattice. Suppose the lattice was in some particular vibrational and rotational state. When light is incident on ...
Hari's user avatar
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1 vote

Selection rules in spectroscopy

The way light interacts with atoms can be modelled by the electron cloud responding to the EM field of light. The response for low intensity light is predominantly dipolar. The dipole operator is odd ...
Superfast Jellyfish's user avatar
1 vote

Constrained Brilloiun zone sum to integral

Why do you have to begin with a switch to an integral? You could simply expand your initial sum using the properties of $\delta$ as $$S=\sum_{\vec{k}_1,\vec{k}_2}{|\Delta_{\vec{k}_1}|^2|\Delta_{\vec{...
Ruslan's user avatar
  • 29.6k
1 vote

Molecular Rotational energies and frequencies of diatomic molecule

You can treat this classically if you consider your diatomic molecule as a rigid rotor. The classical rotational energy is expressed in terms of the angular momentum $J$ $$ E_{rot} = \frac{1}{2} \...
MST's user avatar
  • 321
1 vote

Raman vs Fluorescence, scattering vs absorption, classical vs quantum

The main difference between the two is the time scale, as you've already discussed a bit in your question. The other main Physical difference is that fluorescence is the result of relaxation from an ...
kw111's user avatar
  • 11
1 vote

Phonon scattering process in raman spectroscopy

Just to add some more notes to Steve's response: This process only involves one $D$ phonon, which has energy approx 1335 cm${}^{-1}$ and is located at a Kohn anomaly at the $K$-point of the Brillouin ...
BlueUpsilon's user avatar

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