1
$\begingroup$

Here are 3 typical videos of fractal wood burning: video 1, video 2 and video 3.

As can be seen in all the videos, the different Lichtenberg figures develop simultaneously from both the positive and negative electrodes as the electric current follows leader lines within the wood that represent the pathways of least resistance. However, due to the high resistance of the wood, it heats up and burns to form carbon, which is a good conductor, and which allows the burning to move outwards from the electrodes. Multiple burn paths quickly develop and simultaneously expand from each electrode to produce quite stunning and unique Lichtenberg figures.

Surely, with DC electric current (voltage in the 2000 volt range and high amps are used) consisting of the one-way movement of electrons, a single Lichtenberg figure should be expected to grow from negative electrode and expand towards the positive electrode. So, exactly why do Lichtenberg figures develop simultaneously from each electrode if the burning is caused by electrons moving from the negative electrode to the positive electrode? (And, yes, the Lichtenberg figures are not true fractals)

David J

$\endgroup$
3
  • 1
    $\begingroup$ Although it has nothing to do with your question, I think it would be good to mention, for the benefit of anyone reading about this for the first time, that it has killed many hobbyists and will kill you if you make the slightest mistake. Here's a video about that. $\endgroup$
    – benrg
    Commented Aug 6 at 7:23
  • $\begingroup$ The main takeaways from that video are that rubber-soled shoes won't protect you because of the high voltage (I don't think video-2 guy's rubber mat will help either), and GFCI won't protect you because the high-voltage side of the circuit is isolated from the mains by the transformer. $\endgroup$
    – benrg
    Commented Aug 6 at 7:30
  • $\begingroup$ I agree. Nobody should play with this type of setup until they fully understand the risks and how to avoid getting electrocuted. Multiple layers of safety are required. Too many amateurs have died already and the risks should not be overlooked. $\endgroup$
    – Excentrix
    Commented Aug 7 at 10:17

1 Answer 1

0
$\begingroup$

The effect of the battery is to create a potential difference between the anode and the cathode. Wood itself can be classified as a dielectric material, and becomes polarized in the presence of an external electric field.

In the examples you are watching the process of dielectric breakdown by what some call a disruptive device.

What causes the propagation patterns from both electrodes are polarized ions in the material of different charge (e.g. the ions are either positively or negatively charged depending on the charge of the electode).

Lightening is a great example, since it actually evolves both from the ground and the air as well.

At the molecular level there is a common model of how dielectric breakdown occurs. The breakdown voltage plays an important part in the operation of diodes and other semiconductor devices such as transistors.

So to recap, the battery creates an electric field which creates ions of different charge at opposite electodes. The potential causes the ions to propogate to the oppositely charged electrode creating the burn patterns from each electrode as the wood undergoes dielectric breakdown.

Update: Since the OP asked below, I wanted to highlight my response:

the only other item that I would add at the moment is that it is likely the conversion of the wood to charcoal that allows for the propagation of the lines. I found a rather interesting discussion of Electrically Conductive Charcoal that is prepared from biomass that might help. As far as which node and the effects of charge, if the wood is charge neutral initially it's indifferent to the polarity of the potential, it's the potential that matters to drive the process

The last point is that propagation isn't intelligent, it just knows that a potential exists, so it is neutral in opinion as to which electrode the path is forged from.

$\endgroup$
2
  • $\begingroup$ I have posed the same question on several other Physics discussion groups but, despite over 200 reads, you are the only one to attempt an explanation. So, thank you very much, but unfortunately I don’t think that you have nailed it because dielectric breakdown is momentary event (e.g. arcing) and I don’t believe ions are significantly involved. I hope others will put forward their explanation and I will put my ideas forward in the near future. $\endgroup$
    – Excentrix
    Commented Aug 7 at 9:17
  • $\begingroup$ @Excentrix I guess I am not fully understanding the question. The only other item that I would add at the moment is that it is likely the conversion of the wood to charcoal that allows for the propagation of the lines. I found a rather interesting discussion of Electrically Conductive Charcoal that is prepared from biomass that might help. As far as which node and the effects of charge, if the wood is charge neutral initially it's indifferent to the polarity of the potential, it's the potential that matters to drive the process pubs.rsc.org/en/content/articlehtml/2017/ra/c7ra07349f $\endgroup$
    – Freedom
    Commented Aug 8 at 11:01

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.