1
$\begingroup$

In the two-slit interference experiment, how can we determine where a point P on the screen is in the diffraction pattern by giving the maximum or minimum on which it lies or the maximum and minimum between which it lies. Given that the slit widths are each $a$, their separation is $d$, the wavelength is $\lambda$, the viewing screen is at a distance $D$ and the distance between P and the central maxima is $y$.

I am not sure if we use the formula $asin\theta=m\lambda$ to calculate $m$, since I don't know whether this formula can be used in double slit diffraction. Or we should use another method to find out whether P is the maximum/minimum?

$\endgroup$
0
$\begingroup$

For Young's Double Slit Experiment the $n^{th}$ order maxima is given by $$Y_{n}=\frac{n\lambda D}{d}$$ where D is the distance to the viewing screen and d the spacing between the two slits.

For the $n^{th}$ order minima we use $$Y_{n}=\frac{(2n-1)\lambda D}{2d}$$

$\endgroup$
  • 1
    $\begingroup$ But what I want to know is the position of P in the diffraction pattern, not the interference pattern. $\endgroup$ – RLee Mar 29 at 10:51
  • $\begingroup$ Y gives us the distance of point P from the centre of the screen. Whether there is constructive or destructive interference can be known from which multiple of (lambda)D/d it is. $\endgroup$ – Nixnyete Mar 30 at 10:10

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.