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Quantum electrodynamics (QED) is the quantum field theory believed to describe electromagnetic interaction. It is the simplest example of a quantum gauge theory, where the gauge group is abelian, U(1).

1 vote
2 answers
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Non-invariance of the Interaction term in QED lagrangian

The interaction term in the QED Lagrangian $$\mathcal{L}_{int}=e\bar\psi\gamma^\mu A_\mu\psi$$ changes under a gauge transformation $$A_\mu\rightarrow A_\mu+\partial_\mu\chi$$ Doesn’t it affect the QE …
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4 votes

Why is the energy of $2s_{1/2}$ greater than the energy of $2p_{1/2}$ after the Lamb shift i...

However, the discussion here says that Lamb shift affects only S state. The statement that Lamb shift affects only $s$ states is only approximately correct i.e., true in first order radiative cor …
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3 votes
2 answers
528 views

Can a Lagrangian with only non-negative mass dimensional couplings be non-renormalizable?

In the introduction part of this renowned paper by S. Coleman and E. Weinberg, the authors write The quartic self-coupling is required for renormalizability, to cancel the logarithmic divergence …
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3 votes
1 answer
408 views

What are the observable effects of finite pieces of the loop corrections in QED?

I'm lost amidst the calculation of regularization and renormalization process in QED. In addition to the divergent piece in the in the self-energy correction (similarly in vacuum polarization correcti …
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2 votes
1 answer
372 views

Quantization prescription for an interacting field theory

To my understanding, unlike free fields, interacting fields cannot be expanded in terms of Fourier modes, with the Fourier coefficients representing creation and annihilation operators. Then is it pos …
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0 votes
2 answers
729 views

Variance of an interacting quantum field in its vacuum state

A non-interacting quantum field $\hat{\phi}(x)$ can be decomposed into $a_{\textbf{k}}$ and $a_{\textbf{k}}^\dagger$. This enables us to calculate the variance of a free field. For example, the varian …
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1 vote
1 answer
197 views

Can the cyclotron radiation be called a Bremsstrahlung process?

The term 'bremsstrahlung' is usually reserved for the emission of electromagnetic radiation caused by $(1)$ acceleration or deceleration of the charged particle by an electric field and $(2)$ in prese …
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6 votes
3 answers
1k views

Running of $\alpha$ and scattering amplitudes

Consider a QED scattering process $e^-+e^-\rightarrow e^-+e^-$. The scattering crosssection at the tree-level depends on the square of the fine-structure constant $\alpha$ (apart from the electron mas …
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15 votes
2 answers
4k views

Does classical electrodynamics have $U(1)$ symmetry? If yes, how?

Quantum electrodynamics (QED) is based on $U(1)$ symmetry. What happens to this symmetry in classical electrodynamics? Addendum The books on classical electrodynamics such as J. D. Jackson, does not …
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3 votes
2 answers
306 views

Does Bremsstrahlung refer to the radiation produced exclusively by deceleration?

A charged particle, decelerated by the electric field of another charged particle, typically an atomic nucleus, emits electromagnetic radiation, called Bremsstrahlung. This process typically happens i …
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1 vote
1 answer
676 views

Implication of breakdown of scale invariance for problems with intrinsic length or time scales?

According to Wikipedia article on scale invarince, the equations for electric (and magnetic) fields : $$\nabla^2\vec{E}=\frac{1}{c^2}\frac{\partial^2\vec{E}}{\partial t^2}\hspace{0.3cm}\text{and}\hspa …
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8 votes
1 answer
952 views

Electric charge conservation in a superconductor

In a superconductor, $U(1)$ gauge symmetry is spontaneously broken. But $U(1)$ gauge symmetry is responsible for conservation of electric charge. Then it appears to me that the electric charge conserv …
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1 vote
0 answers
303 views

Radiative correction to the charge form factor $F_1$ in QED

In QED, one can calculate the correction to the form factor $F_2$. To the lowest order, $F_1=1$ and $F_2=0$. At one loop, it is found that $F_2(0)$ receives a non-zero finite correction which is relat …
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3 votes
1 answer
366 views

What are the asymptotic momentum eigenstates? Dressed quanta or quanta of free theory?

Suppose I consider an interacting theory, say QED (with electrons and photons). Let, free electrons, I mean the quanta of the free Dirac Lagrangian. The dressed electron differs from the free electron …
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1 vote
1 answer
308 views

Quantizing the orbital angular momentum of a free Electromagnetic field

It can be shown that the total angular momentum of a free electromagnetic field is given by (for example, in the book A Modern Introduction to quantum field theory by Maggiore, page 98, Eq. (4.82)) $$ …

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