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Results for relativistic addition of velocities
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104 votes

What does general relativity say about the relative velocities of objects that are far away ...

What does general relativity say about the relative velocities of objects that are far away from one another? Nothing. … Answer: They don't have any well-defined velocity relative to us. The relativistic speed limit of c is a local one, not a global one, precisely because velocity isn't globally well defined. …
user avatar
54 votes
Accepted

If absolute velocity does not exist, how can we say a rocket accelerates in empty space?

Within the context of Newtonian mechanics, there's a simple answer: velocities are not absolute, but differences in velocities are. So you can state that acceleration occurs unambiguously. … In special relativity, this is a bit more complicated because of relativistic velocity addition, but all observers can unambiguously compute a "proper" acceleration for every object, which is the acceleration …
knzhou's user avatar
  • 105k
40 votes

Did the new image of black hole confirm the general theory of relativity? (M87)

It was found that the velocity profile of the central 20 pc of the gas disk possessed a Keplerian profile (i.e., $v \propto r^{-1/2}$) as expected if the gas was orbiting in the gravitational potential … Note that the measured gas velocities on opposite sides of the central body differ from each other by roughly 1000 kilometers per second. …
Chiral Anomaly's user avatar
33 votes

What speeds are "fast" enough for one to need the relativistic velocity addition formula?

difference between Galilean and relativistic velocity addition starts in the fourteenth decimal place. … For example, a satellite in low-Earth orbit has a speed of $$ v = \frac{2\pi R_\oplus}{90\rm\,minutes} \approx 7500\,\mathrm{m/s} \approx 2\times10^{-5}c $$ and so has relativistic corrections $(v/c)^ …
rob's user avatar
  • 94.2k
26 votes
4 answers
2k views

trouble reconciling doppler shift for energy and momentum of light

The net momentum of the light will match that of an equivalent mass moving at the speed of the resonator, the net energy will match the relativistic total energy of that mass at that speed, and the net … they are the same as the energy and momentum of an equivalent rest mass with the velocity of the enclosing resonator. …
Paul Kienitz's user avatar
26 votes
Accepted

Einstein's return to aether

In terms of relativistic physics: whatever experimental setup you are using: there is no such thing as attributing a velocity vector of the experimental setup with respect to the relativistic Ether. … [Later addition] The underlying point is that relativistic physics attributes physical properties to spacetime. John Wheeler expressed that as follows. …
Cleonis's user avatar
  • 22.6k
24 votes

How do moving charges produce magnetic fields?

Next he intends to prove that when the observer locates himself in the frame of the moving test charge, he will see, in addition to the regular electrostatic Coulomb (repulsion) force acting on the test … charge, an additional repulsion in the $+x$ direction whose origin is entirely relativistic. …
Francisco Muller's user avatar
22 votes

Would there be no time in a universe with only light?

Speed has a definite meaning, i.e. , the absolute value of the velocity vector, which is given as $({\rm d}x/{\rm d}t,~{\rm d}y/{\rm d}t,~{\rm d}z/{\rm d}t).$ There is no mathematical meaning in the phrase … In addition recent studies show that an arrow of time exists just because of gravitational interactions . …
anna v's user avatar
  • 235k
21 votes
Accepted

How to derive $E=mc^{2}$?

In addition, one assumes conservation of momentum. We do a thought experiment involving a closed box containing two objects of mass $\mathtt{M}$. … Due to the recoil of the light, the masses will move, but the velocities will obviously be very small (for macroscopic objects). …
Count Iblis's user avatar
  • 10.3k
21 votes
3 answers
5k views

Thought experiment and possible contradiction between electromagnetism and special relativit...

[See Figure 1-(b)] The weird point is that $B$ measures a resultant velocity $w$ for the charge which complies with the relativistic velocity addition as: $$w=\sqrt{(\alpha_uv)^2+u^2},$$ where $\alpha_u … as reaching a terminal velocity of $v$. 2- The experiment is carried out away from any gravitational field. …
Mohammad Javanshiry's user avatar
19 votes
Accepted

Is Zitterbewegung an artefact of single-particle theory?

The other big misunderstanding was that the x,y and z-components of the velocity operator do not commute while they do so in the non-relativistic theory and therefor the operator must be wrong, they thought … If the inherent M and P values change because of external B and E fields (by addition) then the electron accelerates. Chiral representation Now what about the c in the velocity operator. …
Hans de Vries's user avatar
19 votes
2 answers
2k views

How to understand the emergent special relativity in the superfluid?

Although made up of non-relativistic atoms, the low-energy excitations of superfluid, i.e. the phonons, are said to be "relativistic". … I believe this should be a fundamental feature of relativity, but I do not see how to prove it. The velocity addition formula for sound is not the same as that for light. …
Everett You's user avatar
17 votes

Phase space volume and relativity

1-\beta v^1)},\quad \overline{v}^3~=~\frac{v^3}{\gamma(1-\beta v^1)}, \quad\text{(rel. velocity addition)}\tag{14} $$ and $$ \overline{x}^1_0~=~\frac{x^1_0}{\gamma(1-\beta v^1)}, \quad \overline{x … G. van Weert, Relativistic kinetic theory, 1980. …
Qmechanic's user avatar
  • 213k
16 votes

Why and how is the speed of light in vacuum constant, i.e., independent of reference frame?

The relativistically correct speed addition rule is the following: $$s=\frac{v+u}{1+\frac{vu}{c^2}}$$ When $\frac{vu}{c^2}$ is close to zero (in other words when the velocities invloved are much less … As you approach the speed of light, the energy given to you by the force causing the acceleration basically contributes more and more to the increase of your mass and less and less to the increase of your …
Sklivvz's user avatar
  • 13.7k
16 votes

Motivation for form $L = T - V$ of Lagrangian

This turns out to be true only on a riemannian manifold; the fact this is almost always true in classical mechanics is an "accident" due to the postulates of classical (non relativistic) mechanics. … Because newtonian mechanics postulates state that the state of a system is completely determined by the knowledge of all positions and velocities of its constituents at a given instant. …
user91126's user avatar
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