For a real object, a concave mirror always forms real and inverted images when object is between infinity and focus and forms virtual and erect when object is between focus and pole , but in the following example , why is there a virtual and INVERTED image Example: When we look in the spoon from concave side .

  • 1
    $\begingroup$ That's a real image, why do you think it's virtual? You can look at real images without projecting them onto a screen. $\endgroup$ Mar 12, 2022 at 17:20

1 Answer 1


Expanding a little on Sebastian Riese's comment, your face is much more than $R=2f$ away from the spoon. [The spoon is very curved, so the radius of curvature $R$ is small (probably less than 5 cm).] A ray diagram will show rays converging to points on a diminished inverted real image between $f$ and $2f$ from the mirror. But there's no screen, so the rays continue on beyond the image and enter your eye as rays diverging from points on the image.

[Because the spoon is so curved, and not even part of a sphere, the 'thin mirror' theory that I've just appealed to holds only approximately, and the image will be a distorted one.]


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.