# Physically, why an oscillating voltage source doesn't see the inductor or the capacitor at resonance?

In an RLC circuit the Mathematics says that some voltage is stored in the LC portion of the circuit, and the rest goes to the resistors, unless the source is oscillating at the resonance frequency.

I get the Math, but I just don't get it physically, why is the resonance frequency is so special? I guess it has something to do with the Energy exchange between the inductor and capacitor, but then how does this take place in the beginning of the operation when both the inductor and capacitor are empty of Energy.

Thanks, looking forward to reading from you.

• In the comment below, you are asking "ignore the transient state" and yet in the question you say "how does it take place in the beginning". The time from "beginning" to "steady state" is the transient state, and you either ignore, it, or you don't. That makes it unclear what you are asking. – Floris Jan 6 '18 at 19:00
• He said that they're different states, so I urged him just to concentrate on the steady state as a beginning. – Raafat Abualazm Jan 6 '18 at 19:44
• "I get the Math" - you've considered then a source of the form $v(t) = V_0\,e^{i\omega_0t}u(t)$ where $u(t)$ is the Heaviside step function? – Alfred Centauri Jan 7 '18 at 1:11
• After tking the inverse Laplace, so yes. – Raafat Abualazm Jan 7 '18 at 13:06
• I want o understand it physically. What actually happens. – Raafat Abualazm Jan 7 '18 at 13:06