Initially capacitor 2 is uncharged . Later it is connected with pre-charged-capacitor 1 in an open circuit . So,yet in this arrangement capacitor 1 cannot charge capacitor 2 .
My question is- as no current is flowing , the top plate & bottom plate of capacitor 2 & bottom plate of capacitor 1 are in the same potential.Always true for this arrangement regardless how many charges there are on capacitor 1.So, why does the potential of bottom plate of cap. 2 & bottom plate of cap. 1 become same magnitude always?Will there any modification happen on the plates at the moment of connecting these 2 capacitors in an open circuit?