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Forced Vibrations are the vibrations under the influence of an external periodic force.

Their amplitude depends on the frequency of the external force. If it is equal to the natural frequency of the vibrating body then the amplitude is very large but when it is not equal then the amplitude is very small.

I am unable to understand this established relation between frequency and amplitude and why does this thing(which I stated above) happens.

P.S. : I am a tenth grader so please avoid the use of complicated terminologies.

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  • $\begingroup$ try understanding hyperphysics.phy-astr.gsu.edu/hbase/sound/reson.html , hyperphysics.phy-astr.gsu.edu/hbase/oscdr.html $\endgroup$
    – anna v
    Commented Sep 1, 2016 at 17:52
  • $\begingroup$ This can really only be understood in mathematical terms. $\endgroup$
    – Gert
    Commented Sep 1, 2016 at 18:22
  • $\begingroup$ @Gert I have a little doubt(different from this question) can you clarify it please? $\endgroup$
    – user116688
    Commented Sep 1, 2016 at 18:24
  • $\begingroup$ If an object has a natural (resonance) frequency and you impose another frequency on it then eventually the object ends up 'following' the forced frequency. The transition from natural to forced frequency is mathematically complicated but not really important. If say your hand held drill runs at say 2000 rpm then soon enough the whole drill will vibrate at that frequency. $\endgroup$
    – Gert
    Commented Sep 1, 2016 at 19:18
  • $\begingroup$ @Gert why is it said that when the pitcher gets filled with water its sound becomes shriller but on the contrary I feel it is opposite $\endgroup$
    – user116688
    Commented Sep 1, 2016 at 19:20

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