3
$\begingroup$

Well, we know that circularly/elliptically polarized light is made up from orthogonal components. So is it possible then to create circularly/elliptically polarized light by combining horizontally and vertically polarized light? It seems to make perfect sense to me.

EDIT: Clarification: I mean by creating circularly/elliptically polarized light in the laboratory (though beam-splitters ?, I don't know) by combining different light beams of horizontally/vertically polarized light.

$\endgroup$
  • $\begingroup$ Yes, it can. $\endgroup$ – ACuriousMind Jul 2 '14 at 17:22
  • $\begingroup$ Clarification: Are you asking whether you can express a circular polarized wave in a basis of linearly polarized components? Because that's certainly true. $\endgroup$ – Ryan Lafferty Jul 2 '14 at 17:25
3
$\begingroup$

Yes, this is possible. The device that makes this possible is called a polarizing beam splitter, which will transmit or reflect light according to its polarization. Thus, it will split diagonal or circular light into its horizontal and vertical components, and when used in reverse it will undo the process (it has to).

Note, however, that you will in general require a pretty exceptional interferometric stability to achieve this. You certainly require both beams to originate from the same source so that they have a definite phase relationship to each other; you would split the beam in two, polarize it in different directions, add a delay stage to control the relative phase, and then combine them using a polarizing beam splitter. The thing is, though, that you need the relative delay to be very tightly controlled, as a few tens of nanometers of difference in the path length will change the polarization from diagonal to circular. This is essentially doable but it is and fiddly, and requires very careful alignment - but that is optical physics in a nutshell.

$\endgroup$
  • $\begingroup$ What for a source you have to use? $\endgroup$ – HolgerFiedler Jul 3 '14 at 3:49
  • $\begingroup$ Some sort of laser, preferably a continuous-wave one, but which kind is not that important. What is important is that the coherence length be as large as possible, which will make everything else easier. $\endgroup$ – Emilio Pisanty Jul 3 '14 at 21:07

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.