I've been reading the chapter on plasmon polaritons and polarons, and I have come to a halt trying to understand this part of the chapter:
The dielectric function of the free electron gas follows from (6) and (7): $$ \text{(CGS)}\quad \epsilon(\omega) = 1-\frac{4\pi ne^2}{m\omega^2}; \qquad \text{(SI)}\quad \epsilon(\omega) = 1-\frac{ne^2}{\epsilon_0m\omega^2}. \tag{8} $$ The plasma frequency $\omega_p$ is defined by the relation $$ \text{(CGS)}\quad \omega_p^2=4\pi ne^2/m; \qquad \text{(SI)}\quad \omega_p^2 = ne^2/\epsilon_0m. \tag{9} $$ A plasma is a medium with equal concentration of positive and negative charges, of which at least one charge type is mobile. In a solid the negative charges of the conduction electrons are balanced by an equal concentration of positive charge of the ion cores. We write the dielectric function (8) as $$ \epsilon(\omega) = 1-\frac{\omega_p^2}{\omega^2},\tag{10}$$ plotted in Fig. 1.
If the positive ion core background has a dielectric constant labeled $\epsilon(\infty)$ essentially constant up to frequencies well above $\omega_p$, then (8) becomes $$ \epsilon(\omega) = \epsilon(\infty)-4\pi ne^2/m\omega^2 = \epsilon(\infty)\left[1-\bar\omega_p^2/\omega^2\right],\tag{11} $$ where $\bar\omega_p$ is defined as $$ \bar\omega_p^2 = 4\pi ne^2/\epsilon(\infty)m. \tag{12} $$ Notice that $\epsilon=0$ at $\omega=\bar\omega_p$.
I just need to know how we arrive at equation no. 11 and equation no. 12. In particular, what does the $\infty$ in $\epsilon(\infty)$ signify?