Timeline for What is $\epsilon(\infty)$ in $\epsilon(\omega) = \epsilon(\infty)[1-\bar\omega_p^2/\omega^2]$, in Kittel's solid state book?
Current License: CC BY-SA 3.0
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| Oct 11, 2016 at 10:03 | vote | accept | Sad_lab_rat | ||
| Oct 11, 2016 at 9:57 | history | edited | Emilio Pisanty | CC BY-SA 3.0 |
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| Oct 11, 2016 at 9:56 | answer | added | Emilio Pisanty | timeline score: 2 | |
| Oct 11, 2016 at 9:50 | comment | added | Emilio Pisanty | @lemon No, that's pretty much completely wrong. Please have a closer look. | |
| Oct 11, 2016 at 9:42 | history | edited | Emilio Pisanty | CC BY-SA 3.0 |
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| Oct 11, 2016 at 9:30 | comment | added | lemon | Yes, stick $\omega=\infty$ into (10) and what do you get? | |
| Oct 11, 2016 at 9:18 | comment | added | Sad_lab_rat | umm.. I know that part but in equation 10 we had 1- (value) but in 11 we have $\epsilon(\infty)$ - (value). Does equation 10 assume that $\epsilon(\infty)$ is 1? Thanks for pointing out that $\infty$ stands for high frequency limit. :) | |
| Oct 11, 2016 at 9:12 | comment | added | lemon | Use (10) to evaluate $\epsilon(\infty)$ and combine that with (8)+(9) and rearrange to get (11)+(12). And $\epsilon(\infty)$ represents the dielectric constant in the limit of high frequencies (it converges). | |
| Oct 11, 2016 at 9:08 | history | asked | Sad_lab_rat | CC BY-SA 3.0 |