If I have a typical Drude dielectric permittivity:
$$\epsilon(\omega) = \epsilon_{\infty} - \frac{\omega_p^2 \tau}{\omega^2\tau + i\omega}$$
Now, decomposing $\Re{(\epsilon(\omega))}$ and $\Im{(\epsilon(\omega))}$:
$$\Re{(\epsilon(\omega))}=-\frac{\omega_p^2}{\omega^2+1/\tau^2} + \epsilon_\infty$$ $$\Im{(\epsilon(\omega))} = \frac{\omega^2_p}{\omega^3 \tau+1/\tau}$$
Now, the imaginary part is the important one, because it relates the permittivity to conductivity (which is what I want).
$$\epsilon_{\text{im}}(\omega)= \frac{\sigma(\omega)}{\omega \epsilon_0}$$
So, why does equating the imaginary part and the above equation not yield the correct answer?
$$\sigma(\omega)=\frac{\omega_p^2\epsilon_0}{\omega^2\tau+1/\tau}$$
Should be:
$$\sigma_D(\omega) = \frac{\epsilon_0\omega_p^2 \tau}{1-i\omega\tau}$$
Where am I going wrong?