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5 votes

Why does $J^2$ only commute with one of $Jx, Jy, Jz$ and not all?

It's certainly true that $J^2$ commutes with each of $J_x$, $J_y$ and $J_z$. Additionally, it is true that for each of $J_x$, $J_y$ and $J_z$, a set of simultaneous eigenstates between that operator ...
Jonomyster's user avatar
4 votes
Accepted

Extra energy by applying torque?

In both cases the collisions are inelastic (as the bullet stops inside the block), so some of the initial kinetic energy is converted to heat due to friction between the block and the bullet. The ...
Peter's user avatar
  • 2,007
3 votes

Beta decay of 6-Helium

Hans Bethe and Philip Morrison give the following "hand-waving" answer to this question on pages 226-227 of the 2nd edition of their influential non-textbook on nuclear physics titled ...
Noah Bray-Ali's user avatar
3 votes

Possible errata Landau and Lifshitz in $\S29$ Matrix elements of vectors in Quantum Mechanics Third Edition

I don't know what is wrong with your reasoning, since it seems to return the right result in the special case where $A_{yy}=A_{zz}$. That said, I never saw this approach, and I searched in Landau'book ...
Ruffolo's user avatar
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3 votes
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Possible errata Landau and Lifshitz in $\S29$ Matrix elements of vectors in Quantum Mechanics Third Edition

The identity to use is: $$[p_i,r_j]=-i\hbar\delta_{ij}$$ You are doing something wrong: $$[L_z,r_x]=[r_xp_y-r_yp_x,r_x]=r_x[p_y,r_x]-r_y[p_x,r_x]$$ $$=0-r_y (-i\hbar \delta_{x,x})=i\hbar r_y$$ It ...
Mauricio's user avatar
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2 votes

What is predicted to happen for electron beams in the Stern-Gerlach experiment?

In 2015, someone did this experiment. The electron beam does split! Observing the spin of free electrons in action(Stern-Gerlach experiment by free electrons) I'll quote a paragraph in the result of ...
Marvyn Hsu's user avatar
2 votes

Total orbital angular momentum of closed orbital shell

Can anyone please help me in understanding why total orbital angular momentum of a closed orbital is zero? The total orbital angular momentum is obtained by constructing "multiplets." The ...
hft's user avatar
  • 23.3k
2 votes

Collision of rotating sticks

The angular velocity vectors produce a resultant vector just like any other vectors do. The combined spin axis is shown in the diagram below as the dashed red diagonal line. The red point labeled B ...
KDP's user avatar
  • 10.1k
2 votes

Why is the spin degree of freedom associated with angular momentum?

I will give a more mathematical take on the answer, mainly taken from the following lecture notes: https://scholar.harvard.edu/files/noahmiller/files/representation-theory-quantum.pdf It boils down to ...
EigenAle's user avatar
  • 304
2 votes

Why is the spin degree of freedom associated with angular momentum?

Spin is linked to angular momentum because spin is linked to symmetry under rotations. When a Lagrangian has symmetry under rotations, there is a conserved quantity associated with that symmetry. We ...
Andrew Steane's user avatar
2 votes

Why is the spin degree of freedom associated with angular momentum?

Because it is angular momentum. More correctly, it's an angular momentum operator. Spin operators follow the conmutation relation $$[S_i,S_j]=i\hbar\varepsilon_{ijk}S_k.$$ Any three operators $S_i$ ...
agaminon's user avatar
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2 votes

How to test whether a 2-particle Hamiltonian is rotationally invariant?

Rotational invariance means the hamiltonian is invariant under all rotations, so it commutes with all generators of such. If you only had one particle, so if you extinguished the second one, $\hat{H} =...
Cosmas Zachos's user avatar
2 votes

Why does $J^2$ only commute with one of $Jx, Jy, Jz$ and not all?

$\vec{J}^2$ actually commutes with all three $J_x$, $J_y$ and $J_z$. So $\vec{J}^2$ have common eigenstates with $J_x$ and have common eigenstates with $J_z$. How is it possible? Those are different ...
OON's user avatar
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2 votes

In a 2-electron system (such as Helium atom), is the Total Angular Momentum quantum number $j = \ell$?

No. The Pauli principle is a statement for the entire state, not just the spin part. It is perfectly possible to have $s=0$ - the antisymmetric spin singlet - if the spatial part is symmetric - say $\...
ZeroTheHero's user avatar
  • 47.8k
2 votes

Is linear momentum always conserved in absence of external forces

Both linear and angular momentum must be conserved, regardless of whether or not mechanical energy is conserved. If impacting the rod at the end produces less linear momentum in the rod than impacting ...
Bob D's user avatar
  • 77.9k
1 vote

Hamiltonian is time independent in rotating frame

While it's true that the dot product form of $H$ suggests rotational invariance, we must remember that the spin operator $\vec{S}$ itself transforms under rotations. Let's denote the components of the ...
Willy Wallace's user avatar
1 vote
Accepted

Deriving the normalization factors of $SU(2)$

From the commutation relations of the SU(2) algebra we get $$J_3 J^\pm | m,\alpha \rangle = J^\pm J_3 | m,\alpha \rangle \pm J^\pm | m,\alpha \rangle = (m \pm 1) J^\pm | m,\alpha \rangle.$$ This ...
samcv's user avatar
  • 26
1 vote
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Topological magnon bands, chiral edge states and broken time-reversal symmetry

If you are looking at say Fig. 4(a) in J. Phys.: Condens. Matter 28 386001 or Fig. 1(b) in PRL 117, 227201, the way they get the band structure is by diagonalizing the Hamiltonian on a slab geometry, ...
Nandagopal Manoj's user avatar
1 vote

How to show that $\int d^3 x\; e^{ikx}(x^1 \partial^2-x^2\partial^1)\varphi (x)=0$?

The integral doesn't always identically vanish. Strictly speaking it only vanishes if you approach spatial infinity using a cylindrical geometry. I will do the problem in 2D because the third ...
Vokaylop's user avatar
  • 438
1 vote

Is linear momentum always conserved in absence of external forces

Conservation of linear momentum always applies. In the case of the ball hitting the center of the rod, you know by symmetry that the rod has no rotational momentum or energy. That means that you can ...
BaddDadd's user avatar
  • 593
1 vote
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Graphical representations of the vector model of quantum angular momentum

Your text should indicate this is a graphical shared metaphor in the community to summarize the quantum picture geometrically, of help in rough estimates. Skipping the real McCoy, the cartoon metaphor ...
Cosmas Zachos's user avatar
1 vote

How to test whether a 2-particle Hamiltonian is rotationally invariant?

To determine whether a Hamiltonian possesses a given symmetry, you determine how the symmetries act on the Hilbert space (i.e. the wave functions) and then check if the actions commute with the ...
TLDR's user avatar
  • 3,749
1 vote

Is there an Ehrenfest-like result for the expectation value of orbital angular momentum?

Yes, indeed, it is possible to derive such a result... although it might look somewhat trivial, if compared to position and momentum in an arbitrary potential. Hamiltonian of angular momentum in ...
Roger V.'s user avatar
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