Search Results

We then define the conserved charges for spatial and temporal translation as momentum and energy, respectively; angular momentum is the conserved Noether charge corresponding to invariance of a Lagrangian … (be it mechanical, elecromagnetic or a even a nonphysical financial system) and whether or not the "momentum" correspond in the slightest to the mechanical notion of momentum or whether or not the quantity …

Conservation of momentum is simply an inductively reasoned hypothesis to summarize certain patterns in experimental data. … As I discuss in my answer to the Physics SE question "What is Momentum, Really?" …

So, if you're in deep space and you throw something with mass $m$ in one direction at a speed $v$, its momentum is $m\,v$ in that direction. … The initial total momentum of the system (you + the thrown thing) is nought. So that means that the final total momentum for the system must be nought. …

There has been exchange of momentum and or angular momentum and energy by dint of some interaction. …

So as in the other answers, you can only change a body's motion state by having it transfer the change of momentum to you since the total system's momentum has to be conserved; you feel this transfer of … For me, this is the deepest meaning for momentum, as I describe further in my answer to the Physics SE question What is momentum really?. …

I think you may be getting a bit confused by the assertion: $$\frac{\mathrm{d}^2\, y(x)}{\mathrm{d} \,x^2} \neq \left(\frac{\mathrm{d} \,y(x)}{\mathrm{d}\, x}\right)^2$$ I agree the interpretation i …

It is not that simple. Injury arises from a variation of acceleration with position over parts of the body. In the case of a fall, when the first part of you hits the ground (say your feet) and stops …

Then the "fundamental" answer to your question is "because light has zero rest mass"; to explain further: the 4-momentum norm relationship: $$\frac{E^2}{c^2} - p^2 = m^2 c^2\tag{1}$$ implies a linear relationship … There are several alternatives: You are truly measuring the beam's total energy, in which case, somewhat counter intuitively, you would find you would need a higher energy to produce a given momentum …

Further to Damon Blevins's pithy answer, you need to be stating what an inertial frame is, so that you can measure your acceleration. A practical answer: you carry with you an accelerometer, and if th …

The momentum observable is one such observable. This is nicely summarized by Ehrenfest's theorem $\mathrm{d}_t\,\langle\psi|\hat{p}|\psi\rangle = \langle\psi|[\hat{H},\,\hat{p}]|\psi\rangle$. … it is only the mean of the momentum measurement that is conserved. …

There is no straightforward way to calculate the force of impact, because this latter is defined by the deceleration of the egg at the end of its journey as a function of time. In turn, this decelerat …

This is a follow on question from Physics SE Question "Can a Skydiver Land On a Large Slide and Survive?". User Steeven gives this answer here. User Dargscisyhp asks: What is it exactly that …

this question begins and ends with the canonical commutation relationship (CCR), the ubiquitous $[\hat{X},\,\hat{P}]=i\,\hbar\,\mathrm{id}$ where of course $\hat{X}$ and $\hat{P}$ are the position and momentum … space wherein: $$\begin{array}{lcl}\hat{X} f(x) &=& x\,f(x)\\ \hat{P} f(x) &=& -i\,\hbar\,\mathrm{d}_x\,f(x)\end{array}$$ This being so, if we want to transform to a co-ordinate system wherein the momentum …

AS for momentum: this is not relevant here as the reaction force from the grating supplies the change in momentum, but I think your title doesn't summarize your true question as well as it might. …

At staging, significant change in momentum / trajectory of the payload-bearing stages can only arise from high impulse transfer between the payload bearing and jettisoned stage; this statement is a reformulation … of conservation of momentum. …