All Questions
6 questions
1
vote
2
answers
1k
views
How to calculate work for irreversible adiabatic processes?
By the first law, we know $\text{d}U=\delta Q+\delta W$ and, on adiabats, we know $\text{d} U=\delta W$. But what is $\delta W$ for irreversible adiabatic processes? Take a thermally isolated ...
1
vote
1
answer
41
views
The work and reversibility of an adiabadically stretched band
I currently working on this. More specifically I have a question about Problem 2.8 (solution on page 34 and exercise on page 25 of the pdf). I have 4 questions
1.
In the solution for b) the author ...
- 131
0
votes
4
answers
82
views
Is there an equivalent of "adiabatic" for work (i.e. a workless transformation)?
In Fermi's Thermodynamics (1937), Chapter I, §1, he defines an isochore transformation as
a transformation during which the system performs no external work
He then discusses the case where the ...
- 183
0
votes
3
answers
1k
views
Why does the reversible adiabatic expansion do more work on the surroundings compared to the irreversible adiabatic expansion?
I am wondering why a reversible adiabatic expansion results in a higher work output on the surroundings though the irreversible adiabatic expansion has to overcome the frictional force and therefore, ...
- 45
0
votes
2
answers
6k
views
Work done in adiabatic process irreversible and reversible
Work done for adiabatic reversible process is $$(P_1V_1 - P_2V_2)/(γ-1)$$ but this is also the work done for adiabatic irreversible process. How?
-1
votes
2
answers
40
views
Why the irreversible work carried in an adiabatic condition never causes change in internal energy?
I saw the lecture of thermodynamics on the MIT opencourse ware . In that lecture , the professor said that change in internal energy in an adiabtic process is caused by only reversible work , and not ...
- 239