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I saw this question about placing a dipole in a conducting shell, what should the $E$ field be? This post clears my questions about the outside field- the conductor's electrons will rearrange themselves to cancel out the dipole's $E$ field.

My question is, what is the field inside the sphere? The dipole's potential $V = \frac{1}{4 \pi \epsilon_0}\frac{p \cdot \hat{r}}{r^2}$ on the sphere's surface is not necessarily equal, so it does not match the equipotential boundary condition as a valid potential field should do.

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  • $\begingroup$ Where is the dipole located within the sphere? What is its orientation? $\endgroup$
    – Brian Bi
    Commented Jan 24, 2023 at 13:51
  • $\begingroup$ @BrianBi A perfect dipole at the center of the sphere $p$ facing one direction $\endgroup$
    – Lab
    Commented Jan 25, 2023 at 4:16
  • $\begingroup$ You should try re-posting the question with that detail included, and a description of how you've tried to solve it and what you're stuck on. $\endgroup$
    – Brian Bi
    Commented Jan 25, 2023 at 4:20

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