I have been looking into different suspensions for a torsional pendulum setup, and came across this paper by Quinn comparing (round) wires and (ribbon) strips.
You can find the article at doi: 10.1088/0026-1394/34/3/6
In equation (2) in the paper, the torsional constant of a round wire is given as:
$$ c_w = \frac{\pi r^4}{2L}\left(F + \frac{Mg}{\pi r^2}\right) $$
where, $r$ is the radius of the wire, $L$, the length, $M$, the mass of the load, and $F$ is the shear modulus of the suspension material.
They then mention that the stress term ${Mg}/{\pi r^2}$ is always much smaller than $F$ and therefore the restoring torque of a wire is always dominated by the elastic component.
This is the part that I have a bit of trouble understanding. Consider, $M = 2$ kg, $r = 30$ $\mu$m, $F = 53$ MPa $= 5.3 \times 10^{7}$ N/m$^2$
These values were approximated from the experimental values described in the paper
Then, ${Mg}/{\pi r^2} \approx 2 \times 10^{11}$ N/m$^2$
This is clearly larger than the shear modulus term, contrary to the previous statement about the elastic component always being the dominating factor. Can some please explain where I might be going wrong here? Much thanks!