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When an elevator goes up, the upward normal force of a person standing in the elevator increases due to the acceleration of the elevator. As a result, there is an upward normal net force. So, shouldn't the person be floating as an impact of the upward force?

But in reality, it is the opposite case. I feel a force downward, I feel heavier.

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    $\begingroup$ Relative to the building, the person is "floating" upwards as a result of the force the elevator imparts on it. $\endgroup$
    – noah
    Jun 29 at 12:32
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Answer Diagram

For understanding this, you have to specify the frame of reference. The person is floating up, as mentioned by Noah's comment.**

Ground Frame: Here, the elevator and the man move up with 'a' acceleration. The normal force, as you rightly mentioned, is greater than the weight of the man, so relative to the ground (or the building) the man does seem to be floating up, as the elevator is going upwards.

Elevator frame: Since the elevator is accelerating, this is a non inertial reference frame, so we have to add pseudo forces when we have to analyze motion from the point of view of the elevator.

Here, in the elevator's reference frame, the man is experiencing not two, but three forces: His own weight, the normal force exerted on him by the elevator, and the pseudo force 'ma' (where m is the mass of the man). Since neither the man nor the elevator has any acceleration in this frame, the forces should be equal, i.e.

Normal force = ma+mg

So, for an observer sitting inside the elevator, the man does not float up, and is stationary.

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Relative to an observer on the ground, or to someone stationary in the building, you would be rising upwards.

But in your own frame of reference, inside the elevator, you would not float. But the downward force due to your mass (your weight) and the (inertial) force downward due to the upward acceleration of the elevator, will point in the same direction. That is, inside the elevator $$F=mg+ma=\text{normal force}$$ where $a$ is the upward acceleration of the elevator, and $F$ will also be equal to the normal force exerted by the ground on you.

To demonstrate this, if you have a mass of say $80kg$ and the elevator accelerates upwards at $10ms^{-2}$, if you put a bathroom scale on the floor of the elevator and stood on it, this force would be $$F=80g+80\times10\approx 1600N$$

So you would feel like you weighed about two times your original weight. So yes you do feel heavier.

Note that if the elevator were moving up with a constant velocity, you would feel the same (no acceleration).

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