Consider a plasma in a star. Now in a plasma electrons are so excited that they can no longer be held by the electromagnetic field of the nucleus. But then when we are talking about cores or red giants or white dwarfs themselves they have the electron degeneracy pressure which is due to the potential well caused by the electromagnetic field itself. Does that mean that those electrons once again come under the influence of the electromagnetic force? But doesn't that go against the definition of a plasma?
1 Answer
Electron degeneracy pressure is not caused by any electromagnetic interaction. It is an "ideal" effect that would be present in any high density gas of indistinguishable, non-interacting fermions.
By constraining the fermions to have high density (with gravity in this case), you force electrons to occupy states well above zero momentum and kinetic energy, since the Pauli Exclusion Principle forbids more than one electron to occupy the same quantum state.
It is this kinetic energy, even at low temperature, that produces degeneracy pressure.
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$\begingroup$ Yes but when you talk about a quantum state aren't they the result of the electromagnetic potential well and hence the electromagnetic force? $\endgroup$ Commented Mar 25, 2020 at 8:32
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1$\begingroup$ @user43470 No. Uncharged fermions can also be degenerate. Electromagnetic interactions provide a 1% modification to ideal degeneracy pressure in white dwarfs. $\endgroup$– ProfRobCommented Mar 25, 2020 at 8:34
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1$\begingroup$ The density of quantum states in a spin 1/2 fermion gas is $8\pi p^2/h^3\ dp$, where $p$ is the particle momentum. Ultimately, the particles are confined by gravity in this case. $\endgroup$– ProfRobCommented Mar 25, 2020 at 8:43
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1$\begingroup$ @user43470 There is no need for any confining potential (except if it weren't for gravity, the electrons would disperse). The density of quantum states is given per unit volume. No details of any volume or potential appear in the expression. $\endgroup$– ProfRobCommented Mar 25, 2020 at 10:10
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1$\begingroup$ @user43470 ecee.colorado.edu/~bart/book/book/chapter2/ch2_4.htm $\endgroup$– ProfRobCommented Mar 25, 2020 at 10:39