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**De Broglie's explanation for Bohr's Quantization Condition**

In de Broglie's explanation for Bohr's quantization condition, why do we not use $2\pi r = n\lambda/2$, why do we use $2\pi r = n\lambda$?

We know that in waves on strings, for standing waves creation in a string between two rigid supports, we use "Length of String" $ = n \lambda/2$. Why do we not use a similar concept here?

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    $\begingroup$ Draw a picture with, say, three-and-one-half wavelengths going around a circle. Do you see a problem? $\endgroup$
    – G. Smith
    Commented Sep 26, 2019 at 16:26

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If the perimeter is not a whole number multiple of ${\lambda}$, the next time the wave completes a revolution it will not coincide with the previous wave. The waves will superimpose and over a period of time eventually cancel itself. The waves must perfectly coincide to exist. Hence the allowed orbits have a radius which satisfies $2{\pi}r = n{\lambda}$

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