I am looking for a proof using Bernoulli's equation that that for $Q=(Area)(Velocity)$, $Q_{in}>Q_{out} \Rightarrow P_{inside}>P_{outside}$. I read that for a computer, if the case fans blow a higher volumetric flow rate in than out, then the PC case is positive pressure, however I seem unable to prove this. My attempt is shown below, with the assumption that $z_1=z_2$, $P_{1,g}=0$, and the subscript g indicates gage pressure. My control volume is the inside of a computer case, and subscript 1 represents outside of the control volume (flowing in), and subscript 2 represents inside the control volume (flowing out):
\begin{align} \frac{P_1}{\rho}+\frac{V_1^2}{2}+z_{1}&=\frac{P_2}{\rho}+\frac{V_2^2}{2}+z_{2} \\ \frac{V_1^2}{2}&=\frac{P_{2,g}}{\rho_{air}}+\frac{V_2^2}{2} \Rightarrow \\ \frac{P_{2,g}}{\rho_{air}}&=\frac{V_1^2-V_2^2}{2} \Rightarrow \\ P_{inside,g}&=\rho_{air} \frac{V_{entering}^2-V_{leaving}^2}{2} \end{align}
Since $V=\frac{Q}{A}$, then the pressure inside is also dependent on the area of a fan, which contradicts what I read saying $Q_{in}>Q_{out} \Rightarrow P_{inside}>P_{outside}$. This is a bit confusing to me and I'd appreciate any answers that I can get.
