This is in reference to the synchronization condition detailed in Einstein's 1905 paper:
If at the point $A$ of space there is a clock, an observer at $A$ can determine the time values of events in the immediate proximity of $A$ by finding the positions of the hands which are simultaneous with these events. If there is at the point $B$ of space another clock in all respects resembling the one at $A$, it is possible for an observer at $B$ to determine the time values of events in the immediate neighbourhood of $B$. But it is not possible without further assumption to compare, in respect of time, an event at $A$ with an event at $B$. We have so far defined only an “$A$ time” and a “$B$ time.” We have not defined a common “time” for $A$ and $B$, for the latter cannot be defined at all unless we establish by definition that the “time” required by light to travel from $A$ to $B$ equals the “time” it requires to travel from $B$ to $A$. Let a ray of light start at the “$A$ time” $t_A$ from $A$ towards $B$, let it at the “$B$ time” $t_B$ be reflected at $B$ in the direction of $A$, and arrive again at $A$ at the “$A$ time” $t^′_A$.
In accordance with definition the two clocks synchronize if
$t_B − t_A = t^′_A − t_B$.
If $B$ is moving at a constant velocity w.r.t. $A$, and if $A$ wants to perform a synchronization check, how does he find out the value of $t_B$ ? Does he measure it himself or does $B$ communicate the value of $t_B$ to $A$? If $A$ measures $t_B$ himself, could a synchronization check performed by $B$ yield a different result? (since then $B$ would have to measure "$A$ time")