This theorem can be used to prove Archimede's Principle in a region with a non-uniform gravitational field.
The weight of the displaced fluid is
$$\vec W=\int_\Omega \rho \vec g(\vec r)~\mathrm d\Omega.$$
Let us consider a body fully immersed. Then the buoyancy force is given by
$$\vec B=-\oint_\Gamma p(\vec r)~\mathrm d\vec \Gamma =-\int_\Omega\vec\nabla p~\mathrm d\Omega,$$
where $p(\vec r)$ is the pressure, $d\vec \Gamma$ is the oriented area element and the given theorem is used.
A static fluid satisfy
$$\vec\nabla p=\rho\vec g.$$
Plugging this into the integral for $\vec B$ and comparing with the integral for $\vec W$ we see that the buoyancy force equals the weight of the displaced fluid even when the gravitational field is non-uniform.
Edit
Proof of the result claimed by the OP:
Consider a vector field $f(x)\vec v$, where $f$ is a scalar field and $\vec v$ is a constant non vanishing vector. By the divergence theorem:
$$\oint_\Gamma f\vec v\cdot ~\mathrm d\vec \Gamma=\int_\Omega \vec\nabla\cdot (f\vec v)~\mathrm d\Omega.$$
Since $\vec\nabla (f\vec v)=\vec v\cdot\vec\nabla f$, you get
$$\vec v\cdot \oint_\Gamma f~\mathrm d\vec \Gamma=\vec v\cdot\int_\Omega\vec\nabla f~\mathrm d\Omega.$$
Since this holds for any constant vector $\vec v$ we get the result
$$\oint_\Gamma f~\mathrm d\vec \Gamma=\int_\Omega\vec\nabla f~\mathrm d\Omega.$$
In fact I have seen people calling this the "gradient theorem".