I am wondering about the spectrum of light that is often shown pictorially as a distribution of power, say, from sunlight. My question is: does this indicate that each wave of light contains all of those frequencies added together or is it that each wave has a single frequency and there are countless of them following the distribution indicated by the typical picture of the light spectrum.
4 Answers
This is a more QM explanation.
The light from the Sun is white light (contrary to popular belief it is not yellow), and contains all visible wavelengthts.
This means, that the light coming from the Sun contains photons of all visible wavelengths (400-700nm).
The human eye is able to detect even one single photon. Now when you look at the direct Sunlight, your eye receives photons of all visible wavelengths (400-700nm), and the cones and rods in your retina are sensitive to these specific wavelength photons. Since in the case of white light from the Sun, all receptors are activated in your retina, you will combine this as white light (it appears yellow to you because of the atmosphere's scattering effect on the photons).
You are asking whether each EM wave has its own frequency, or each EM wave has a combination of different frequency lights.
You are confused because of the classical and QM model of light.
Now the original equations (Maxwell) and model of classical EM waves and light treats light as an EM wave, having a certain frequency, thus a certain energy, and color.
The QM model of EM waves, where a herd of photons build up the classical EM wave, work perfectly together with the classical one.
Each photon has its own wavelength, frequency, thus its own color (our eyes interpret it as color).
The EM waves that make up the white light coming from the Sun are built up by a herd of photons, each photon having its own wavelength (color), and our eyes receptors combine the different photons into a single combined light (in the case of the Sun it is white).
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$\begingroup$ Do you mean that the sunlight is white when emitted or after passing through the atmosphere? $\endgroup$– Roger V.Commented Jun 9, 2021 at 5:16
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$\begingroup$ @my2cts correct, I mean the energy of the photon, that relates to frequency and wavelength. $\endgroup$ Commented Jun 9, 2021 at 21:53
The answer depends on what you mean by "each wave of light." If you mean that you isolate a very narrow ray of sunlight as through a very small hole, then it will contain all the wavelengths. If you mean that you isolate a part of the sunlight using a diffraction grating or prism spectrometer, then it will contain a very narrow band of wavelengths. Maybe you can elaborate on what you mean.
Light is a muxture of waves of different frequencies. Note also, that power spectrum is not the amplitude of these waves, but their intensity - i.e., the light electric field squared and averaged over the device reaction time. In practice, to construct spectral density, one would use spectrum analyzer: filtering light in a narrow spectral band and measuring intensity of this band - this is then done for all frequencies.
Think about how electromagnetic radiation is generated. Electrons and protons emit photons. The wavelengths of this photons depends from the surrounding temperature, for the protons it depends from the chemical elements (H, He, ...., C). Furthermore it depends from the gravitational potential and the velocity of gas streams. Perhaps this are not all parameters. The spectrum is the sum of all of this photons.
Waves are oscillating energy distributions. One see them then a star is rotating as fast as the magnetic field influence the emitted photons in a way that we can discover a waveform distribution of electromagnetic radiation. From our sun we get a continious flow of photons of different energy levels. They don't have oscillating energy distribution.
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$\begingroup$ So are you saying that each photon has a constant, single frequency for its associated wave? $\endgroup$– ZenPylonCommented Aug 29, 2015 at 17:35
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$\begingroup$ @ajdecker1022 The photon is the wave. Each photon has a frequency and a wavelenght. In thermal radiation the photons not in phase and have different frequencies over a wide range $\endgroup$ Commented Aug 30, 2015 at 10:10