If isospin is conserved in a given strong interaction, can we say that it is certainly allowed and it's not needed to check other conservation rules like baryon number, electric charge etc. ?
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Absolutely not!
Reactions preserving isospin, but violating P, C, B, are completely disallowed by the strong interactions.
Those violating Q or CPT, or Lorentz-Invariance, etc, are disallowed by all interactions (that we know of).
Fine print . Actually, in real life strong interactions, isospin (and hence G) is an approximate symmetry, explicitly broken by a very small amount, $(m_d-m_u)/\Lambda_{QCD}$~1%, by virtue of the inequality of current quark masses. Such small effects can be monitored, but they are irrelevant to your rough-and-ready diagnostic use here.
answered Jan 16, 2022 at 19:55