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Cosmas Zachos
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Absolutely not!

Reactions preserving isospin, but violating P, C, B, are completely disallowed by the strong interactions.

Those violating Q or CPT, or Lorentz-Invariance, etc, are disallowed by all interactions (that we know of).

Fine print . Actually, in real life strong interactions, isospin (and hence G) is an approximate symmetry, explicitly broken by a very small amount, $(m_d-m_u)/\Lambda_{QCD}$~1%, by virtue of the inequality of current quark masses. Such small effects can be monitored, but they are irrelevant to your rough-and-ready diagnostic use here.

Absolutely not!

Reactions preserving isospin, but violating P, C, B, are completely disallowed by the strong interactions.

Those violating Q or CPT, or Lorentz-Invariance, etc, are disallowed by all interactions (that we know of).

Fine print . Actually, in real life strong interactions, isospin is an approximate symmetry, explicitly broken by a very small amount, $(m_d-m_u)/\Lambda_{QCD}$~1%, by virtue of the inequality of current quark masses. Such small effects can be monitored, but they are irrelevant to your rough-and-ready diagnostic use here.

Absolutely not!

Reactions preserving isospin, but violating P, C, B, are completely disallowed by the strong interactions.

Those violating Q or CPT, or Lorentz-Invariance, etc, are disallowed by all interactions (that we know of).

Fine print . Actually, in real life strong interactions, isospin (and hence G) is an approximate symmetry, explicitly broken by a very small amount, $(m_d-m_u)/\Lambda_{QCD}$~1%, by virtue of the inequality of current quark masses. Such small effects can be monitored, but they are irrelevant to your rough-and-ready diagnostic use here.

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Cosmas Zachos
  • 66.3k
  • 6
  • 110
  • 248

Absolutely not!

Reactions preserving isospin, but violating P, C, B, are completely disallowed by the strong interactions.

Those violating Q or CPT, or Lorentz-Invariance, etc, are disallowed by all interactions (wethat we know of).

Fine print . Actually, in real life strong interactions, isospin is an approximate symmetry, explicitly broken by a very small amount, $(m_d-m_u)/\Lambda_{QCD}$~1%, by virtue of the inequality of current quark masses. Such small effects can be monitored, but they are irrelevant to your rough-and-ready diagnostic use here.

Absolutely not!

Reactions preserving isospin, but violating P, C, B, are completely disallowed by the strong interactions.

Those violating Q or CPT, or Lorentz-Invariance, etc, are disallowed by all interactions (we know of).

Absolutely not!

Reactions preserving isospin, but violating P, C, B, are completely disallowed by the strong interactions.

Those violating Q or CPT, or Lorentz-Invariance, etc, are disallowed by all interactions (that we know of).

Fine print . Actually, in real life strong interactions, isospin is an approximate symmetry, explicitly broken by a very small amount, $(m_d-m_u)/\Lambda_{QCD}$~1%, by virtue of the inequality of current quark masses. Such small effects can be monitored, but they are irrelevant to your rough-and-ready diagnostic use here.

Source Link
Cosmas Zachos
  • 66.3k
  • 6
  • 110
  • 248

Absolutely not!

Reactions preserving isospin, but violating P, C, B, are completely disallowed by the strong interactions.

Those violating Q or CPT, or Lorentz-Invariance, etc, are disallowed by all interactions (we know of).