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When the surface of Langmuir probe is a plane, the I-V curve has a shape like that illustrated in this figure:

enter image description here

One can clearly note the existance of two regions of sauration, in which the current has a fairly constant value. The thing is, I d'ont know why this happens.
1. why do the electronic/ionic currents saturate?

On the other hand, for a cylindrical probe, the electronic current don't saturate, as shown here:

enter image description here

The reason is as follows: the electronic current increases because of edge effects due to the increase of the collection area by the expansion of the sheath. A follow up question is:
2. why does the electons sheath expand in the first place?
(I know that the collection area of a cylindrical prob is not limited by the physical area of the probe's tip).

I've read many references, but I didn't find satisfactory answers to these tow questions. Can anyone elaborate on these points please? Thanks in advance!

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To answer your first question, we have to remind ourselves on a very important property of the plasma: if you insert a test charge into a plasma, plasma particles of the opposite charge will form a space charge cloud around that test charge cancelling its electric field such that the test charge is not "seen" by the plasma outside of this space charge cloud. The distance over which the test charge is shielded is the Debye length which depends on plasma temperature and density.

If we replace the test charge with a Langmuir probe, the exact same thing will happen: depending on plasma temperature and density, the potential of the probe will be shielded over a certain distance (Debye length) and it is not possible to attract charged particles outside this sheath. This is why the current saturates.

Your second question implies that such a saturation does not exist in reality (i.e. the lab). This is indeed the case, as illustrated by the characteristic you have plotted. A simple explanation for the non-saturation is the Orbital Motion Limit model. Let's consider a spherical Langmuir probe. As explained above, a sheath will be formed around the probe shielding its potential. If, however, charged particles from the plasma fly by the probe, passing it, they will be attracted by the probe's potential (or repelled). This will change their trajectory. If they are very slow, their trajectory can change such that they are collected by the probe (similar to celestial object movement, hence the name of the model). This will increase the effective probe surface. The higher the probe bias (the applied voltage), the more likely it is to "catch" passing charges. This is why the drawn current increases further with increasing bias voltage.

Note that edge effects, leading to higher electric fields, are not part of the above mentioned model. Higher (local, i.e. at the edges) electric fields, however, will simply result in an increased effective probe surface based on the same explanation.

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  • $\begingroup$ Thank you so much for the great answer! $\endgroup$
    – Samà
    Commented Sep 14, 2019 at 21:57
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    $\begingroup$ @Samà I'm glad it helped $\endgroup$
    – Alf
    Commented Sep 15, 2019 at 20:04

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