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Graphs

These three graphs are from my textbook. It states that the acceleration in 1) is positive, 2) is negative and 3) is zero and can be told by looking at the slope.

What I understand from the graph is in the picture above. How can I conclude the signs of acceleration from that information in graphs 1 and 2?

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    $\begingroup$ If you can understand the velocity change, can't you understand the acceleration sign? If you can't understand the former, look for slope of the graph. $\endgroup$ Commented Jul 30, 2017 at 18:39
  • $\begingroup$ I understand about velocity change and slope. Like in graph 1, velocity is changing from negative to positive. Velocity is changing so the object is accelerating. But how does that tell anything about the sign of acceleration? $\endgroup$
    – Raknos13
    Commented Jul 30, 2017 at 18:42
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    $\begingroup$ Velocity us changing from negative to positive means that the body is accelerating, as the velocity is increasing. $\endgroup$ Commented Jul 30, 2017 at 18:49
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    $\begingroup$ If it's accelerating, then it's +a, if retarding, then -ve. $\endgroup$ Commented Jul 30, 2017 at 19:24
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    $\begingroup$ @Raknos13 You had a misconception, not him. $\endgroup$
    – user279106
    Commented Jul 30, 2021 at 13:43

4 Answers 4

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The acceleration is the rate of change of velocity (i.e., how fast it's changing in time).

A positive acceleration means increasing values of velocity, for example, as in your picture, that the velocity (slope) goes from negative to positive values. A negative $a$ means decreasing values for $v$.

When the velocity is neither growing, nor getting smaller, its rate of change is zero: $a=0$.

Graphically, when a curve in the $x$ vs. $t$ plot has its concavity pointing up, $a$ is positive; when it's pointing down, $a$ is negative.

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  • $\begingroup$ A negative $a$ doesn't necessarily mean decreasing $v$; it only applies when $v$ is positive. If $v$ is negative, negative $a$ would mean increase in speed. $\endgroup$
    – Raknos13
    Commented Jul 30, 2017 at 19:02
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    $\begingroup$ Numerically, it's a decrease: $-5<-3$, the speed, though, yes, would be increasing -- but speed and velocity aren't the same. $\endgroup$
    – stafusa
    Commented Jul 30, 2017 at 19:04
  • $\begingroup$ @R3l1c A negative $a$ makes $v$ more negative. This is what is meant when people say "decreasing". $\endgroup$
    – Steeven
    Commented Jun 2, 2018 at 8:07
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    $\begingroup$ @R3l1c, velocity has a sign associated with it but speed doesn't. Mathematically, if something has a negative velocity and a negative acceleration, the object is speeding up, but the velocity is decreasing (getting more negative). $\endgroup$ Commented Jul 7, 2018 at 21:23
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In the first graph the velocity is changing from negative to positive with respect to time, i.e. $\frac{dv}{dt} > 0$. Acceleration $a = \frac{dv}{dt}$ and thus a is positive.

In the second graph it's just the opposite.

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  • $\begingroup$ No, the graphs are position-time graphs, not velocity-time graph. Please read the question once again. $\endgroup$
    – user279106
    Commented Jul 30, 2021 at 13:47
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In the graph 1, body is moving with a constant acceleration, In the graph 2, body is moving with a constant retardation, and, In the graph 3, body is moving with a constant velocity.

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On average, acceleration is related to the change in slope over time

$$ a_{\rm ave} = \frac{ {\rm slope}(B) - {\rm slope}(A) }{ {\rm time}(B) - {\rm time}(A) } $$

fig

Case Slope at A Slope at B Acceleration Sign
1) negative positive positive
2) positive negative negative
3) positive positive zero
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