Take this phase diagram :
At the point "A" I will have a liquid, at point B a gas.
But what I want to know is : which phase do I have at point C.
I know that this is precisely where the phase transition occurs, but imagine I put the pressure and temperature at $(P_c,T_c)$. Will my system have a liquid phase with the "first molecule of gas close to appear", or will it be a gas will the "first molecule of liquid close to appear" ? (I puted quotes because I don't know what is the exact word in english for this). How can I know ?
Does it in fact depend of where I was previously ?
Like if I start from A, go to C then on C it will still be a liquid. But if I started at B and changed temperature and pressure to go to C I would have a gas on C ?
[Edit because of the comment] : To be more accurate in my question, I know from here https://www.uam.es/personal_pdi/ciencias/evelasco/master/tema_III.pdf that two phases coexisting are not stable thermodynamically.
Here is the curve they have :
And what they say :
Inside the spinodal line the fluid is unstable, since $\kappa_T^{-1}<0$ , which implies $\frac{\partial P}{\partial V} > 0$, which is not possible for a stable material. If we disregard these unstable states (between ‘a’ and ‘b’), predicted by the theory, we are left with the gas and liquid branches, from small volumes up to ‘a’, and from large volumes up to ‘b’ (i.e. the regions where $\kappa_T^{-1}>0$).
So in the context of thermodynamic we are looking for stability. Thus between between $V_1$ and $a$, $b$ and $V_2$, we have metastability and between a and b we have unstability.
So in conclusion we don't have thermodynamic equilibrium (because we are looking for stable states) when we have two phases (liq+gas).
Thus how can we have a mixture at thermodynamic equilibrium with this explanation, I don't get...