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Results tagged with quantum-spin
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user 56599
Fundamental characteristic property of particles which together with orbital angular momentum acts as the generator of rotations and which doesn't have a classical equivalent but is sometimes compared to and contrasted with classical intrinsic angular momentum.
3
votes
Accepted
Why can we factorize the state of a particle?
Yes, the factorizability is an axiom. Formally, it is states as
The Hilbert space of a composite system is the Hilbert space tensor product of the state spaces associated with the component syst …
- 4,820
2
votes
Accepted
Klein-Gordon-Equation contains no Spin
The components of every field must satisfy the KG equation, regardless of its spin. This makes sense, since it is nothing more than just the Einstein energy momentum relation.
The idea is that the KG …
- 4,820
1
vote
Behaviour of quantum spins
If I understand your question correctly, there seems to be a misunderstanding in your statement
As far as I understand, in quantum mechanics, you can identify any spin half particle to be fermion …
- 4,820
2
votes
Accepted
$j=\frac{1}{2}$ addition of angular momentum
The addition rule has an absolute value sign. That is
$$ s_{tot}= |s_1 + s_2|,|s_1 + s_2 - 1|, \ldots, |s_1 - s_2| $$
And so the smallest value you can have is $1/2 - 1/2 = 0$. $s_{tot} $ is the th …
- 4,820
1
vote
Calculating the spin given the baryon wave function
Your equation for $| \psi \rangle $ is
\begin{equation}
|\psi\rangle = \frac{1}{\sqrt{6}}\left(2\big\uparrow\big\uparrow\big\downarrow - \big\downarrow\big\uparrow\big\uparrow - \big\uparrow\big\ …
- 4,820
2
votes
Spin operators in QM
You're reading Griffiths, so I will try to stay within his vocabulary---but to answer your question I have to introduce perhaps some formalism that Griffiths doesnt.
In general, this is the story. M …
- 4,820
1
vote
Commutation relations
Since it appears you are actively working on the problem I will offer a series of hints. Please comment if you need further guidance.
Hint 1: Muonium is a bound state of $\mu^+ e^-$. Note that they …
- 4,820
2
votes
Nature of Spin in QFT
No, the intrinsic spin of a particle is just a consequence of a "particle" being represented by an irreducible representation of the the Poincaré group.
The spin of the particle is determined by the …
- 4,820
4
votes
Accepted
How can I explicitly express the Ising Hamiltonian in matrix form?
For completeness I'll summarize the answer here. After a fun conversation in the comments, we saw that it will be more illuminating to write
$$H=-\sum_ {i=1}^{N-1}
\sigma_i^x \sigma_ {i+1} ^x + h \ …
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