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This tag is for questions regarding the Newtonian model of gravity in which the force between two objects is given by $~GMm/r^2~.$ It is a natural phenomenon by which all things with mass or energy – including planets, stars, galaxies, and even light – attract one another. On Earth, gravity gives weight to physical objects, and the Moon's gravity causes the ocean tides.

14 votes

How can I measure the mass of the Earth at home?

You can make estimates of the Earth's mass $M_\mathrm E$ by estimating its average density $\rho$ and using the formula $M_\mathrm E = \rho \cdot V$, where of course $V= \frac{4}{3} \pi R^3$, so you h …
Gerard's user avatar
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0 votes

Gravity on a doughnut-shaped/Möbius planet

On the torus: Walking towards the inner side of the torus one becomes lighter, because one has gravitational pull under one's feet (which is stronger because it is nearer) and gravitational pull above …
Gerard's user avatar
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3 votes
4 answers
116 views

A little question about $F_g = F_c$

It is already some time ago that I was fluent in classical mechanics. I do not understand a certain detail in the formula $F_{grav.}=F_{centr.}$. Probably I overlook something simple. Suppose mass $m$ …
Gerard's user avatar
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A little question about $F_g = F_c$

In continuation of the answer of Claudio Saspinksi: Choosing M as the inertial frame of reference gives $$\frac{GMm}{r^2} = m\omega^2 r \cdot \frac{M}{M+m}= m\omega^2 r \cdot (1 - \frac{m}{M+m})$$ wh …
Gerard's user avatar
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8 votes
3 answers
2k views

How about an exact solution for the position of a planet as a function of time?

Recently I was surprised to discover that no exact solution for the position of a planet as a function of time exists. I am referring to the two-body problem in a gravitational field where Newtons law …
Gerard's user avatar
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