All Questions
Tagged with semiclassical wavelength
9 questions
4
votes
2
answers
586
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'Slow variation' in WKB approximation as precise mathematical condition
The WKB approximation provides an approximative solution
to the one-dimensional, time-independent Schrödinger equation
$$ -\frac{\hbar^{2}}{2m} \frac{d^{2}}{dx^{2}} \Psi(x) +V(x)\Psi(x)=E\Psi (x)$$
...
- 1,555
0
votes
1
answer
330
views
Why do we rule out orbits with non-constructive interference for the atom? [duplicate]
It is said that de Broglie explained the quantization of Bohr's orbitals with the idea of the "matter wave" of the electron being forced to have orbits where it can interfere constructively ...
- 673
2
votes
2
answers
518
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The link between discrete energy level in quantum mechanics and harmonic series in Acoustics
Consider a quantum square potential well with infinite depth:
$$
V(x)=\begin{cases}
0, &|x|<a \\
+\infty, &\text{otherwise}.
\end{cases}$$
Solving the Schodinger equation of a particle with ...
- 1,365
0
votes
0
answers
65
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Bohr’s Quantisation Condition [duplicate]
I am a grade 12 student from India and my physics textbook does not delve deep in the bohrs quantisation condition but has given us a paragraph to figure out what it is:
“Consider Motion of an ...
2
votes
1
answer
232
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What is the wavelength at the classical turning points using WKB Approximation? [closed]
According to what I know is that a classical turning point in Newtonian Mechanics is a point where a particle has a zero kinetic energy (Total energy is equal to potential energy) and must be ...
1
vote
1
answer
237
views
Why does a stable orbit of $H$ atom contain an integer number of de Broglie wavelengths? [duplicate]
I was trying to understand why a stable orbit of a hydrogen atom has to satisfy that the orbit length must be a multiple of de Broglie wavelength.
I have seen some related questions like This.
But ...
- 107
2
votes
3
answers
1k
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If Bohr model is outdated and we know that there is no such thing as an "electron orbital circumference" then how is $2\pi r=n\lambda$ still valid?
We know that Bohr model is outdated and we know that there is no such thing as an "electron orbital circumference" then how is $2\pi r=n\lambda$ still valid?
Edit :
If the electrons for higher ...
- 212
22
votes
5
answers
13k
views
Why does electron orbital circumference have to be in multiples of de Broglie wavelengths?
Electron orbit circumferences have to be in multiples of its de Broglie wavelength, but what do those 2 have in common?
- 551
3
votes
2
answers
4k
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Bohr / De Broglie postulate (what does $n λ= 2 π r$ imply)
From the Bohr/De Broglie postulate we have n λ = 2πr where λ is the De-Broglie wavelength , r is the radius corresponding to n and n is the quantum number.
An electron in the state n=2 has more ...
