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How do force and mass work with all derivatives of position?

I think if $F(t) = kt^0$ then $$x(t) = x_0 + v_0t + \frac{k}{m}\frac{t^2}{2!},$$ and if $F(t) = kt^1$ then $$x(t) = x_0 + v_0t + \frac{k}{m} \frac{t^2}{2!} + \frac{k}{m} \frac{t^3}{3!},$$ and so on, ...
clara raquel's user avatar
3 votes
1 answer
79 views

What do we get on differentiating the instantaneous displacement function?

I was doing kinematics when a silly question came to my mind. It is as follows: When we differentiate $x(t)$ (position as a function of time), we get $v(t)$ (instantaneous velocity). Doing the reverse,...
PandaScientist's user avatar
1 vote
6 answers
113 views

If a body moves along a path (any path, not just circular) with constant speed, is it's tangential acceleration necessarily zero?

If a body moves along a path (any path, not just circular) with constant speed, is it's tangential acceleration necessarily zero? I could only find general proofs for the case of circular motion and ...
Rebecca Elkouby's user avatar
4 votes
3 answers
2k views

What does "Just before" and "Just after" really mean in physics problems?

So I'm stuck in a dynamics problem that asks what is the acceleration of a body just after A, where A is the point that separates the motion of the body from a curvilinear path to projectile motion. ...
Normal_Vector's user avatar
3 votes
3 answers
653 views

Confusion about successive derivatives of position in circular motion

Suppose we define a unit vector $\vec r$ along radial direction for a particle in uniform circular motion at an angular frequency $\omega$. Then we can write: $$\vec r = \cos(\omega t)\hat i + \sin(\...
Prateek Mourya's user avatar
2 votes
5 answers
346 views

Significance of $\frac{dv}{dx}=0$

Suppose an object is moving with varying acceleration in time. What does it mean when it hits a point where $\frac{dv}{dx}=0$? Does it mean the object has hit maximum velocity? Assume the object ...
Rasputin's user avatar
4 votes
2 answers
312 views

Force and Accleration

It's just a basic question I had when I was studying physics years back, So acceleration have two equations $$a=\frac{F}{m}$$ and $$a=\frac{\text{d}v}{\text{d}t}$$ So by the first equation, if I'm ...
Nimrod's user avatar
  • 171
1 vote
4 answers
58 views

Can we calculate centripetal acceleration by using this method $\frac{\mathbf v_2-\mathbf v_1}{T}$?

If we know the angle between two velocity vectors $\mathbf v_1$ and $\mathbf v_2$, and if we know the time $T$ it takes for the velocity to change from $\mathbf v_1$ to $\mathbf v_2$,then is it ...
Abdullah Al Zami's user avatar
0 votes
2 answers
299 views

Velocity as a property

Is velocity considered to be a property like mass and weight that can be measured at a single moment in time, such as mass of X measured at time T1, or is it a property that needs to be measured over ...
Miles Esfahani's user avatar
0 votes
1 answer
303 views

Computing total derivative of Kinetic Energy w.r.t time

I am confused as to how to take the total derivative $\frac{dKE}{dt}$, where $KE$ is the kinetic energy. I know that $KE = 1/2 *m * \dot{\vec r} \cdot \dot{\vec r}$. From here, if I take derivative ...
User 10482's user avatar
0 votes
1 answer
112 views

Where is the frame information in a time derivative of a physical vector in a moving frame using limits?

In the equation: $$\left(\!\frac{d \vec r}{dt}\!\right)_{\!1}= \left(\!\frac{d\vec r}{dt}\!\right)_{\!0} + \vec\omega_{01}\wedge\vec r$$ How could this be translated to a mathematical definition of ...
mjcmsp's user avatar
  • 1
0 votes
3 answers
84 views

How is velocity defined in circular motion in central force field?

In my view the velocity is change of displacement in the increasing direction of displacement. Now in circular motion in central force field the particle is changing its direction then how is the ...
Nobody recognizeable's user avatar
-1 votes
1 answer
106 views

Radius as a constant while deriving of formula for acceleration in circular motion [closed]

While deriving acceleration in circular motion, we differentiate $\vec{v}=\vec{\omega}\times\vec{r}$ Here we differentiate by product rule and write $\frac{dr}{dt}$ as $v$. So we know $\vec{s} =\vec{\...
user63555's user avatar
1 vote
1 answer
130 views

On the derivative of a vector function

In "An Introduction to Mechanics" by Kleppner and Kolenkow, in the section on the time derivative of a vector: Given $A(t)$ is a vector valued function, then, $$\Delta A = A(t + \Delta t) - A(t)$$ ...
trynalearn's user avatar
-1 votes
1 answer
3k views

How to find Net Force with constant velocity? [closed]

Does having a constant velocity always make the acceleration equal zero? For example: A 5 kg ball is moving at constant velocity of 15 m/s. What is the net force on the ball? If the formula is $F_{...
Dylan Doesmath's user avatar
0 votes
1 answer
2k views

Derivation of centripetal acceleration

While reading HC Verma chapter 7 circular motion I came across a derivation which I couldnt understand. I have marked my doubt with red. I don't understand from where +dw/dt [- i sine +j cos0] came ...
oshhh's user avatar
  • 997
1 vote
2 answers
4k views

Free falling and bouncing back

My confusion arises with free falling body. For a free falling body the displacement ~ time graph has a kink (at the time when the body hit the ground ). at a kink point, a function is not derivable ...
pritam's user avatar
  • 13