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Adjoint of the covariant derivative of a field?

Let's call $D$ the covariant derivative, $T$ the transposition of a field and $*$ its complex conjugate, so $T*$ is the "adjoint". Is: $$(D_{\mu}\Phi)^{T*} (D_{\mu}\Phi)=D^{\mu}\Phi^*D_{\mu}\...
Mathieu Krisztian's user avatar
0 votes
1 answer
83 views

What is the relation between gauge field and Levi-Civita connection?

In field theory, covariant derivative is something like $$D_{\mu}\phi=(\partial_{\mu}-igA_{\mu})\phi$$ while in differential geometry, covariant derivative is something like $$D_{\mu}V^{\nu}=\partial_{...
Baoquan Feng's user avatar
3 votes
0 answers
153 views

d'Alembertian operator in presence of torsion

Consider a Riemann-Cartan 4-dimensional spacetime with torsion. In such a spacetime, I have been asked to compute the d'Alembertian operator acting on a scalar field. Here's what I tried: $$ g^{\mu\nu}...
Faber Bosch's user avatar
1 vote
0 answers
170 views

What is the meaning of $\nabla _{\mu}\nabla _{\nu}\phi(r)$ in general relativity?

I know the covariant derivative of a tensor is $$\nabla_{\mu} V_{\nu}=\partial_\mu V_\nu-\Gamma_{\mu\nu}^{\lambda}V_{\lambda}$$ Now I want to obtain $\nabla_{\mu}\nabla_{\nu}\Phi(x)$ where $\Phi(x)$...
Alice's user avatar
  • 67
2 votes
1 answer
634 views

Covariant derivative on $n$-forms

I am new to form notation. I have recently read that one can write (non-abelian) gauge theory in terms of forms. I am stuck and can't derive this equation below: $$ \nabla_{A} \alpha_p = d \alpha_p + ...
physicsdude's user avatar
0 votes
0 answers
83 views

Doubt of gauge covariant derivatives: how can I derive it?

In the context of general relativity (GR) it is necessary to introduce the notion of covariant derivatives. From the point of view of a basic introduction, we always start to deal with GR in a highly ...
M.N.Raia's user avatar
  • 3,159
2 votes
2 answers
164 views

Is there a equivalent theorem for closed form/ exact form for derivative with respect to fields

For a vector (one-form) $A_\mu$, when \begin{eqnarray} \partial_{[\mu}A_{\nu]}=0 \end{eqnarray} then, there exists a scalar $\phi$ such that \begin{eqnarray} A_\mu =\partial_\mu\phi \end{eqnarray} ...
KayS's user avatar
  • 91
2 votes
1 answer
807 views

The equation of motion for a scalar field in curved spacetime in terms of the covariant derivative

The equation of motion for a scalar field in curved spacetime $$\frac{\partial\mathcal{L}}{\partial\phi}=\frac{1}{\sqrt{-g}}\partial_{\mu}\left[\sqrt{-g}\frac{\partial\mathcal{L}}{\partial\left(\...
Solidification's user avatar
0 votes
0 answers
233 views

Covariant derivative of a composite field and the chain rule

I have a gauge theory with some rather strange covariant derivatives and I am wondering how they act on a composite field like $\psi= \phi\psi'$. In my setup, the covariant derivative acting on a ...
JeffK's user avatar
  • 141
2 votes
1 answer
346 views

Covariant derivative in field theory

I'm reading Physics from Symmetry by Jakob Schwichtenberg and in Chapter 7 equation 7.18 he introduces the covariant derivative when deriving the interaction Lagrangian density for the spin-$\frac{1}{...
Feng's user avatar
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