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Covariant derivative acting on Dirac delta function

Pardon my naive computational question. In my calculations, I encounter the following expression: \begin{equation} \label{eq1} \frac{\delta}{\delta g^{\gamma \epsilon}(z)} \left( g_{\mu \alpha}(x) \...
haj's user avatar
  • 85
3 votes
2 answers
340 views

Understanding the definition of the covariant derivative

I'm currently working my way through the book "Mathematical Methods for Physics - An Introduction to Group Theory, Topology and Geometry" and I think I have a very fundamental ...
HiveFive's user avatar
0 votes
1 answer
80 views

The definition of the Lie Derivative

I am aware that an answer to an almost identical question already exist, however, I found the already existing answer not helpful (at least to my current question). Carroll defines, in his book, the ...
Bilge K. Aksebzeci's user avatar
-1 votes
0 answers
17 views

How to prove that a Lie algebra-valued differential form is exact for the covariant derivative [migrated]

Given a differential $p$-form $\omega^A$ over a smooth manifold with values on some Lie algebra, I wanted to know how could one prove that it can be written as an exact form for the exterior covariant ...
user728261's user avatar
3 votes
1 answer
114 views

Relationship between covariant derivative and metric tensor

In general relativity, the covariant derivative of the coordinate vector is a tensor, equal to $$x^{\mu}_{:\rho} = x^{\mu}_{,\rho} + \Gamma^{\mu}_{\rho\nu}x^{\nu},$$ is it meaningful to equate this ...
Davyz2's user avatar
  • 562
1 vote
0 answers
62 views

A trick for derivatives of thermodynamic quantities [closed]

Starting from $$dU=TdS-PdV$$ We can write, for instance $U(T,V)$ and $S(T,V)$ to obtain: $$\left(\frac{\partial U}{\partial T}\right)_VdT+\left(\frac{\partial U}{\partial V}\right)_T dV=T\left(\frac{\...
Michał Kuczyński's user avatar
3 votes
1 answer
94 views

What happens to $g^{\alpha\beta}_{,\sigma}=-g^{\alpha\mu}g^{\beta\nu}g_{\mu\nu,\sigma}$ when $g_{\mu\nu}\rightarrow \eta_{\mu\nu}$ (weak field limit)?

The equation $$g^{\alpha\mu}_{\,\,\,\, ,\sigma}\,g_{\mu\nu} + g^{\alpha\mu}\,g_{\mu\nu,\sigma} = (g^{\alpha\mu}g_{\mu\nu})_{,\sigma} = \delta^\alpha_{\nu,\sigma} = 0 $$ gives the useful relation $$g^{\...
Khun Chang's user avatar
0 votes
0 answers
38 views

Four-divergence of a vector [duplicate]

The covariant derivatives of a four-vector is $$ \nabla_{\nu}U_{\mu} = \partial_{\nu}U_{\mu} - \Gamma^{\lambda}_{\mu\nu}U_{\lambda} $$ It has the following identity: $$ \nabla_{\mu}U^{\mu} = \frac{\...
user437988's user avatar
0 votes
1 answer
69 views

Is 4-velocity a Vector in the Sense of Covariant Derivative along Worldline

The definition of 4-velocity $U^{\mu} \equiv dx^{\mu}(\tau)/d\tau$, however, we've learnt that the covariant derivative for a vector along a curve parametrized by proper time is, $$\frac{DA^{\mu}}{D\...
Ting-Kai Hsu's user avatar
1 vote
1 answer
98 views

Proving a Superfunction Identity

I am trying to figure out the proof of the identity given between equations (1.11.7) and (1.11.8) in ref. [1], i.e. \begin{align} \Phi'(e^{-K}\,z\,e^K)=e^{-K}\Phi'(z) \tag{1} \end{align} where $z=(...
Susan's user avatar
  • 49
5 votes
1 answer
330 views

Divergence of vector field term-wise

In a spacetime $(M, g)$ the following identity for the divergence of a vector field $X$ holds $$ \nabla_{\mu} X^{\mu} = \frac{1}{\sqrt{-\det g}} \, \partial_{\mu} \big( \sqrt{- \det g} \ X^{\mu} \big)...
Octavius's user avatar
  • 695
1 vote
0 answers
62 views

Adjoint of the covariant derivative of a field?

Let's call $D$ the covariant derivative, $T$ the transposition of a field and $*$ its complex conjugate, so $T*$ is the "adjoint". Is: $$(D_{\mu}\Phi)^{T*} (D_{\mu}\Phi)=D^{\mu}\Phi^*D_{\mu}\...
Mathieu Krisztian's user avatar
0 votes
0 answers
59 views

Covariant derivative with torsion

The covariant derivative is defined (on contravariant vectors) as: $$\nabla_\mu V^\nu = \partial_\mu V^\nu + \Gamma^\nu_{\mu \rho} V^\rho \tag{1}$$ The purpose of the covariant derivative is to ...
Frederic Thomas's user avatar
2 votes
0 answers
46 views

Is a spin connection with torsion possible whereas the affine connection is only Levi-Civita (torsion-free) in Supergravity?

In the paper "Simple Supergravity" from G. Dall'Agata & M. Zagermann (arXiv:2212.10044v2 15 Feb. 2023) on page 8 when it comes to the antisymmetric part of the covariant derivative of ...
Frederic Thomas's user avatar
0 votes
0 answers
159 views

What's the difference? $\nabla_\mu e_\nu=\Gamma_{\mu \nu}^\rho e_\rho~\text{ and }~\partial_\mu e_\nu=\Gamma_{\mu \nu}^\rho e_\rho~?$

What's the difference? $$\nabla_\mu e_\nu=\Gamma_{\mu \nu}^\rho e_\rho~\text{ and }~\partial_\mu e_\nu=\Gamma_{\mu \nu}^\rho e_\rho~?$$ In John Dirk Walecka's book 'Introduction to General Relativity',...
Jianbingshao's user avatar
1 vote
3 answers
98 views

Does (covariant) divergence-freeness of the stress-energy tensor ${T^{\mu\nu}}_{;\nu}=0$ follow from the Bianchi identity?

I'm working through Chap. $30$ of Dirac's "GTR" where he develops the "comprehensive action principle". He makes a very slick and mathematically elegant argument to show that the ...
Khun Chang's user avatar
3 votes
1 answer
133 views

A theorem on page 72 in The Large Scale Structure of Space-Time [closed]

In chapter 3 of the book, page 72, a static observer is defined as $V^{a}\equiv f^{-1}K^{a}$, where $K^{a}$ is a timelike Killing vector field and $f^{2}=-K^{a}K_{a}$. Then, Hawking & Ellis claim ...
Rui-Xin Yang's user avatar
0 votes
1 answer
81 views

Covariant Directional Derivative

How is the covariant directional derivative $\frac{D}{d\lambda}=\frac{dx^{\mu}}{d\lambda}\nabla_{\mu}$ in GR related to acceleration? I am motivated to ask this question because I’ve seen it stated ...
ICOR's user avatar
  • 79
3 votes
1 answer
163 views

Laplace-Beltrami operator for a vector field

For a scalar field $\varphi$, the "wave" operator is defined as follows: $$\Box \varphi \equiv g^{ab}\nabla_a\nabla_b~\varphi = \frac{1}{\sqrt{|g|}}\partial_a\left\{\sqrt{|g|}~g^{ab}~\...
newtothis's user avatar
  • 603
0 votes
0 answers
58 views

Partial derivatives of Christoffel symbols to Covariant derivatives

I wanted to express this thing: $g^{ab}\partial_c\Gamma^c_{ab} - g^{ab}\partial_a\Gamma^c_{cb}$, in terms of a covariant derivative. I figured out that if you swap $a$ and $c$ in the $\partial \Gamma$ ...
Stargazer's user avatar
1 vote
0 answers
50 views

A covariant derivative computation in General Relativity [duplicate]

I am trying to compute $\nabla^\mu\nabla^\nu R_{\mu\nu}$. I proceed as follows: \begin{align} \nabla^\mu\nabla^\nu R_{\mu\nu}&=g^{\mu\rho}g^{\nu\lambda}\nabla_\rho\nabla_\lambda R_{\mu\nu} \\ &...
vyali's user avatar
  • 372
1 vote
1 answer
72 views

Covariant derivative for spin-2 field

I have mostly seen the concept of covariant derivative with regard to spin-1 fields. Is it possible to define the covariant derivative for spin-2 fields as well?
physics_2015's user avatar
1 vote
1 answer
77 views

Does the divergence theorem require the covariant derivative to be metric compatible?

I know this is more of a mathematical question, but it arises in the context of general relativity and uses its language so I thought it would be best to ask it here. I understand that the divergence ...
P. C. Spaniel's user avatar
1 vote
1 answer
114 views

How is this deduced? (Differentiation of tensors)

In Schutz's An Introduction to General Relativity, he talked about how to differentiate tensors. Here is a step that I cannot understand. $$\frac{d\mathbf{T}}{d\tau} = \left( T^{\alpha}_{\beta, \gamma}...
Gene's user avatar
  • 63
0 votes
1 answer
83 views

What is the relation between gauge field and Levi-Civita connection?

In field theory, covariant derivative is something like $$D_{\mu}\phi=(\partial_{\mu}-igA_{\mu})\phi$$ while in differential geometry, covariant derivative is something like $$D_{\mu}V^{\nu}=\partial_{...
Baoquan Feng's user avatar
0 votes
1 answer
75 views

Lie derivative: moving boat on a flowing river

Lie derivatives signifies how much a vector (Tensor) changes if flown in the direction of some other vector. I am thinking the typical moving boat on a flowing river problem where the river is flowing ...
spacetime's user avatar
0 votes
1 answer
346 views

Isomorphism of the tangent space and the space of directional derivatives [closed]

I have already constructed the tangent space to a manifold, denoted $T_pM$, and I have a good basis for it $\{\hat e_{(\mu)}\}$. (I followed the method of equivalence classes of curves tangent at $p$....
hodop smith's user avatar
0 votes
0 answers
46 views

Application of Fermi-Walker derivative to specific problem

I am now reading about the tetrad formalism in GR and I am starting (how not) with the Wikipedia Article: Frame fields in general relativity. In this article, as an example, they show how tetrads can ...
T. ssP's user avatar
  • 533
2 votes
1 answer
190 views

Covariant derivative to the metric determinant?

I am reading the paper Alternatives to dark matter and dark energy, but cannot obtain one specific equation no matter how I tried. So I wrote an email to the author, the following is what he replies ...
user392063's user avatar
2 votes
1 answer
74 views

Closed interval in variation of a field

Let's suppose that $\psi$ is a field so that $$\psi\in\Gamma^\infty(\pi):=\{\psi\in C^\infty(M,E)\ |\ \pi\circ\phi=I_M\}$$ where $E$ is a spacetime bundle over spacetime $M$ and $\pi : E\rightarrow M$ ...
user avatar
0 votes
3 answers
240 views

What is the correct term for $\nabla\phi$? Co-vector or 1-form or both?

In the olden days, $\nabla\phi$ was used to be called a covariant vector (Weinberg used this language in his book Gravitation & Cosmology). But this terminology is considered bad for several ...
Solidification's user avatar
0 votes
1 answer
115 views

Double covariant derivative of a mixed tensor

Let's say, we have a mixed tensor of type (2,1) denoted by $T^{mn}{}_p$ and the goal is to find the expression of $[\nabla_a, \nabla_b] T^{mn}{}_p$ in terms of fundamental tensors. Firstly, I am ...
raf's user avatar
  • 151
1 vote
4 answers
445 views

How to find the double covariant derivative of a general vector?

I have been reading through Carroll's GR textbook and there is a line in the derivation of the Riemann tensor that I do not understand. $$\nabla_\mu \nabla_\nu V^\rho=\partial_\mu(\nabla_\nu V^\rho) - ...
Chris G's user avatar
  • 71
1 vote
0 answers
113 views

Derivation of covariant derivative by means of parallel transport

I've studied covariant derivative in many courses so far, but I got stuck on the definition given by the teacher notes of the exam of Topological QFT. I think that he improperly used the name "...
polology's user avatar
  • 177
1 vote
0 answers
94 views

Del operator confusion [closed]

The very first thing my textbook says is that the Del operator is defined as: $$\vec{\nabla}=\vec{a}^i\nabla_i$$ Where $\nabla_i$ is the covariant derivative and " $\vec{a}^i$ is the curvilinear ...
Krum Kutsarov's user avatar
0 votes
1 answer
113 views

What is the intuition or the derivation of covariant derivative?

I asked this question in mathematics but the answer I got was a bit too abstract for me so I hope that my fellow physicists can give me more of an intuition or an easier explaination of my question. ...
Krum Kutsarov's user avatar
4 votes
2 answers
231 views

Looking for the geometric meaning of the curl of Killing vector fields

From Killing equation $$\nabla_\nu \xi_\mu + \nabla_\mu \xi_\nu = 0$$ it can be shown that $\nabla_\nu \xi_\mu$ is antisymmetric. From it we can construct an antisymmetric tensor $\mathcal{A}_{\mu\nu}$...
Pau Bañón Pérez's user avatar
1 vote
0 answers
118 views

Lie derivative of a one-form

I am going through Nakahara's textbook on geometry and topology in physics. Intuitively, I understand the definition of a lie derivative of a vector field $$\mathcal{L}_xY = \lim_{\epsilon_\to 0}\frac{...
Souroy's user avatar
  • 343
2 votes
2 answers
152 views

How to calculate the rotation at a singularity?

An electrodynamics lecture asks me to prove that $$ \nabla \times \left( \frac{\vec{M} \times \vec{x}}{ |\vec{x}|^3} \right) = \frac{8 \pi}{3} \vec{M} \delta^3(\vec{x})- \frac{\vec{M}}{|\vec{x}|^3}+ \...
F L's user avatar
  • 151
8 votes
2 answers
915 views

How does the covariant derivative satisfy the Leibniz rule?

In Carroll's "Spacetime and Geometry", he states on page 95 (section 3.2) that the covariant derivative, $\nabla$, is a map from $\left(k, l\right)$ tensor fields to $\left(k, l+1\right)$ ...
MBar2269's user avatar
  • 103
1 vote
1 answer
94 views

Is the Lie derivative in a coordinate direction covariant?

Considering a partial derivative of a vector field $w^a$ in x-direction (also called here 1-direction) I can write it as $$\frac{ \partial w^a}{\partial x^1 } = \partial_1 w^a - \Gamma^a_{1c} w^c + \...
Frederic Thomas's user avatar
2 votes
0 answers
57 views

How does the divergence change under a change of frame (with geometric algebra)?

I'm trying to prove equations (85) and (86) from Hestenes' paper Gauge Theory Gravity with Geometric Calculus (ResearchGate version). $$ \dot{\nabla}^\prime \cdot \dot{\underline{f}}(A) = J_f^{-1}[ (\...
foghorn's user avatar
  • 163
1 vote
1 answer
102 views

Variation of Torsion-Free Spin Connection

In the book 'Supergravity' by Freedman and van Proeyen, in exercise (7.27) it is written To calculate [the variation $\delta\omega_{\mu ab}$ of the torsion-free spin connection], consider the ...
vyali's user avatar
  • 372
3 votes
2 answers
201 views

What is difference between an infinitesimal displacement $dx$ and a basis one-form given by the gradient of a coordinate function?

In general relativity, we introduce the line element as $$ds^2=g_{\mu \nu}dx^{\mu}dx^{\nu}\tag{1}$$ which is used to get the length of a path and $dx$ is an infinitesimal displacement But for a ...
Mahtab's user avatar
  • 644
2 votes
1 answer
109 views

Spin connection for a vector field

Using Birrel & Davies convention, the covariant derivative for a field of arbitrary spin in curved spacetime is given by $$\nabla_\mu=\partial_\mu+\Omega_\mu,\tag{1}$$ with $$\Omega_\mu=\frac{1}{2}...
AFG's user avatar
  • 2,349
0 votes
2 answers
329 views

Transformation of Lie derivative of one-form

In the textbook Supergravity ( by Freedman and Proeyen, 2012), they have defined the Lie derivative of a covariant vector with respect to a vector field V on page 139: $$ \mathcal{L}_V \omega_\mu = V^\...
baba26's user avatar
  • 542
2 votes
1 answer
194 views

Derivation of Leibniz Rule for Exterior Derivative

I was reading Sean Carrol's GR book, when on page 85 he introduces the Leibniz rule analogue for exterior derivatives: $$\text d(\omega\wedge\eta) = (\text d\omega)\wedge\eta + (-1)^p\omega\wedge(\...
JS30's user avatar
  • 129
1 vote
0 answers
47 views

Scalar curvature in ADM Formalism (coordinate to coordinate-free transition)

I am attempting to express the scalar curvature in a coordinate-independent manner. Following the works of Bojowald, Thiemann, we have: $$ {}^{(4)}R= {}^{(3)}R+K_{a b}K^{a b}- (K_a^a)^2 - 2\nabla_a v^...
Powder's user avatar
  • 403
1 vote
1 answer
289 views

What is the difference between $\partial_{\mu}$ and $\partial^{\mu}$? [closed]

I've seen in many books both expressions $\partial_{\mu}$ and $\partial^{\mu}$, which are the covariant and contravariant partial derivatives, respectively, and in one of Susskind's books he defined ...
Antoniou's user avatar
  • 751
0 votes
0 answers
103 views

Conceptual confusion about the formula for parallel transport

I am examining the covariant derivative of a vector according to the formula $$\nabla_{\mu}V^{\nu} = \partial_{\mu}V^{\nu} + \Gamma^{\nu}_{\mu \lambda}V^{\lambda}$$ and also operating under the ...
Relativisticcucumber's user avatar

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