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Derivation of lagrange equation in classical mechanics

I'm currently working on classical mechanics and I am stuck in a part of the derivation of the lagrange equation with generalized coordinates. I just cant figure it out and don't know if it's just ...
Jan Oreel's user avatar
2 votes
5 answers
348 views

Why does $\vec{r}\cdot\dot{\vec{r}}=r\dot{r}$?

Why is $$\vec{r}\cdot\dot{\vec{r}}=r\dot {r}$$ true? Before saying anything, I have seen the proofs using spherical coordinates for $$\dot{\vec {r}}= \dot{r}\vec{u_r}+r\dot{\theta}\vec{u_\theta}+r\sin\...
Ulshy's user avatar
  • 69
2 votes
6 answers
274 views

Lagrangian - How can we differentiate with respect to time if $v$ not a function of time?

In the Lagrangian itself, we know that $v$ and $q$ don't depend on $t$ (i.e - they are not functions of $t$ - i.e., $L(q,v,t)$ is a state function.) Imagine $L = \frac{1}{2}mv^2 - mgq$ Euler-Lagrange ...
Giorgi's user avatar
  • 535
0 votes
2 answers
150 views

Does the gradient of potential energy exist independent of coordinates?

Potential energy $U(\vec{r})$ of a conservative force field $\vec{F}$ is defined as a function whose variation between positions $\vec{r}_A$ and $\vec{r}_B$ is the opposite of the work done by the ...
Antonio19932806's user avatar
1 vote
2 answers
181 views

Coordinate basis vectors on tangent bundle (extrinsic view)

Short Version: when we say that $(\pmb{q},\pmb{u}):TQ_{(q)}\to\mathbb{R}^{2n}$ are local coordinates for the tangent bundle of $Q$, which can be viewed as an embedded submanifold of a higher ...
J Peterson's user avatar
1 vote
1 answer
34 views

Derivatives of the lagrangian of generalized coordinates [closed]

I know that $$U= \frac{1}{2} \sum_{j,k} A_{jk} q_j q_k \quad \quad T= \frac{1}{2} \sum_{j,k} m_{jk} \dot{q}_j \dot{q}_k $$ and the lagrangian is $$ \frac{\partial U}{\partial q_k} - \frac{d}{dt} \...
rannasquaer's user avatar
1 vote
1 answer
170 views

Is the order of ordinary derivatives interchangeable in classical mechanics?

I am having trouble with a term that arises in a physics equation (deriving the Lagrange equation for one particle in one generalized coordinate, $q$, dimension from one Cartesian direction, $x$). My ...
user2721127's user avatar
2 votes
1 answer
742 views

Proof that the Euler-Lagrange equations hold in any set of coordinates if they hold in one

This is a question about a specific proof presented in the book Introduction to Classical Mechanics by David Morin. I have highlighted the relevant portion in the picture below. In the remark, he ...
user avatar
0 votes
1 answer
134 views

Velocities - Equation 1.46 of Goldstein 3rd edition

In his derivation of the Euler-Lagrange equations from D'Alembert's principle, Goldstein uses the parametrization (equation 1.45') $$\displaystyle{\vec{r_i}=\vec{r_i}(q_1,q_2, ..., q_n, t)}\tag{1.45'}$...
Daniel's user avatar
  • 113
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1 answer
89 views

Step in derivation of Lagrangian mechanics

There is a step in expressing the momentum in terms of general coordinates that confuses me (Link) \begin{equation} \left(\sum_{i}^{n} m_{i} \ddot{\mathbf{r}}_{i} \cdot \frac{\partial \mathbf{r}_{i}}{\...
jayjay's user avatar
  • 295
1 vote
1 answer
58 views

Energy change under point transformation

How do the energy and generalized momenta change under the following coordinate transformation $$q= f(Q,t).$$ The new momenta: $$P = \partial L / \partial \dot Q = \partial L / \partial \dot q\times ...
LSS's user avatar
  • 990
0 votes
0 answers
85 views

Cartesian coordinate velocity and generalized coordinate velocity

use $x_k$ to denote the kth component of cartesian coordinate, and $q_k$ to denote the generalized coordinate. Taking the derivate of $x_k(q_1,q_2,q_3,t)$ w.r.t. time, we have $$\frac{d x_k(q_1,q_2,...
sunxd's user avatar
  • 105
1 vote
2 answers
461 views

Total time derivatives and partial coordinate derivatives in classical mechanics

This may be more of a math question, but I am trying to prove that for a function $f(q,\dot{q},t)$ $$\frac{d}{dt}\frac{∂f}{∂\dot{q}}=\frac{∂}{∂\dot{q}}\frac{df}{dt}−\frac{∂f}{∂q}.\tag{1}$$ As part of ...
Synchronicity's user avatar
0 votes
2 answers
78 views

Translation of coordinates to generalised coordinates

The translation form $r_i$ to $q_j$ language start forms the transformation equation: $r_i=r_i (q_1,q_2,…,q_n,t)$ (assuming $n$ independent coordinates) Since it is carried out by means of the ...
Jack Jack's user avatar
  • 187
1 vote
3 answers
142 views

Proof of Lagrangian equations [closed]

Context: Trying to proof Lagrangian equations without an explicit usage of the concept of virtual displacement. (disclaimer for happy close-vote triggers: I'm not related to any academic institution ...
pasaba por aqui's user avatar
1 vote
3 answers
353 views

In Euler-Lagrange equations, why we take ${\partial T}/{\partial {x}} $ as zero (when no terms of $x$ is present)?

Basically, why we treat them as independent quantities. I know what a partial derivative is, It means if a function depends on multiple variables, the partial derivative with respect to a particular ...
AMISH GUPTA's user avatar
-1 votes
1 answer
316 views

D'Alembert's principle derivation in Goldstein's Classical Mechanics book [duplicate]

(I could not find any answer to the following question in other related questions posted on SE, so asking it here.) In the derivation of D'Alembert's principle in his "book", Goldstein uses the ...
Kurious's user avatar
  • 15
0 votes
0 answers
55 views

Math question about point transformations

I am trying to prove the classic problem to showcase Lagrangian's scalar invariant property. Namely, that if you have $x_i = \{ x_1, ...., x_n; t \}$ , you can then represent $L(x_1,....,\dot{x_1},.....
Enrique Segura's user avatar
1 vote
1 answer
359 views

How come $\frac{d}{dt}\left(\frac{\partial {r_i}}{\partial {q_j}}\right) = \frac{\partial {\dot r_i}}{\partial {q_j}}$ in Lagrangian mechanics? [duplicate]

It is written in the Goldstein's Classical Mechanics text that $$\frac{\mathrm d}{\mathrm dt}\left(\frac{\partial {r_i}}{\partial {q_j}}\right) = \frac{\partial {\dot r_i}}{\partial {q_j}}=\sum_k \...
Sameer Baheti's user avatar
57 votes
7 answers
10k views

Why isn't the Euler-Lagrange equation trivial?

The Euler-Lagrange equation gives the equations of motion of a system with Lagrangian $L$. Let $q^\alpha$ represent the generalized coordinates of a configuration manifold, $t$ represent time. The ...
Trevor Kafka's user avatar
  • 1,883
0 votes
2 answers
2k views

Derivation of generalized velocities in Lagrangian mechanics

So I know that: $$r_i = r_i(q_1, q_2,q_3,...., q_n, t)$$ Where $r_i$ represent the position of the $i$th part of a dynamical system and the $q_n$ represent the dynamical variables of the system ($n$ =...
user avatar
0 votes
2 answers
2k views

Velocity in generalized coordinates

Consider the expression of velocity in generalized coordinates, $\mathbf v = \frac {d \mathbf x}{dt}$, where $\mathbf x = \mathbf x (\mathbf q(t), t)$. We end up with a total derivative, i.e $$\...
Lo Scrondo's user avatar
1 vote
3 answers
123 views

Lagrange classical relation

I have been studying theoretical mechanics and just now I came cross a formula called "Lagrange classical relation", that is, if we let $q_1$, $q_2$,$\cdot $$ \cdot $$\cdot $, $q _ m$, $t$ be the $...
painday's user avatar
  • 115
0 votes
1 answer
91 views

In central-force mechanics, how do we substitute $ξ=\frac{1}{r}$?

I have taken a look at central-force mechanics in the past, but I still cannot understand how $ξ=\frac{1}{r}$ is substituted to find $\frac{d^2r}{dt^2}$ in terms of ξ. So I know from $F=ma$ that: $$(...
Atom smasher's user avatar
2 votes
1 answer
463 views

What is the function type of the generalized momentum?

Let $$L:{\mathbb R}^n\times {\mathbb R}^n\times {\mathbb R}\to {\mathbb R}$$ denote the Lagrangian (it should be differentiable) of a classical system with $n$ spatial coordinates. In the action $...
Nikolaj-K's user avatar
  • 8,703
15 votes
2 answers
4k views

Why does cancellation of dots $\frac{\partial \dot{\mathbf{r}}_i}{\partial \dot{q}_j} = \frac{\partial \mathbf{r}_i}{\partial q_j}$ work?

Why is the following equation true? $$\frac{\partial \mathbf{v}_i}{\partial \dot{q}_j} = \frac{\partial \mathbf{r}_i}{\partial q_j}$$ where $\mathbf{v}_i$ is velocity, $\mathbf{r}_i$ is the ...
Kit's user avatar
  • 1,483