0
$\begingroup$

I'm currently working on classical mechanics and I am stuck in a part of the derivation of the lagrange equation with generalized coordinates. I just cant figure it out and don't know if it's just basic mathematics or a physics assumption. I hope someone can explain this step to me. I don't understand the transition from the terms involving the partial derivative to the kinetic energy term.

enter image description here

$\endgroup$
1
  • $\begingroup$ Use the chain rule of differentiation of a square. $\endgroup$ Commented Feb 24 at 21:18

1 Answer 1

1
$\begingroup$

Applying the derivative (don't forger the inner derivative): $$\frac{\partial}{\partial\dot{q}_{j}}\left(\frac{1}{2}m_{i}v_{i}^{2}\right)=\frac{1}{2}m_{i}\frac{\partial}{\partial\dot{q}_{j}}v_{i}^{2}=m_{i}\boldsymbol{v}_{i}\frac{\partial\boldsymbol{v}_{i}}{\partial\dot{q}_{j}}$$

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.