Linked Questions

10 votes
2 answers
5k views

Why does a Lorentz scalar field transform as $U^{-1}(\Lambda)\phi(x)U(\Lambda) = \phi(\Lambda^{-1}x)$?

This problem is from Srednicki page 19. Why $U^{-1}(\Lambda)\phi(x)U(\Lambda) = \phi(\Lambda^{-1}x)$? Can anyone derive this? $\phi$ is a scalar and $\Lambda$ Lorentz transformation.
Physics_maths's user avatar
11 votes
1 answer
3k views

Lorentz group representations in QFT: what's the vector space?

In QFT, a representation of the Lorentz group is specified as follows: $$ U^\dagger(\Lambda)\phi(x) U(\Lambda)= R(\Lambda)~\phi(\Lambda^{-1}x) $$ Where $\Lambda$ is an element of the Lorentz group, $\...
zzz's user avatar
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3 votes
2 answers
3k views

Tensors in Quantum Mechanics and tensors from linear algebra

Consider the following two understandings of tensors: Given $k$ vector spaces $V_1,\dots,V_k$ one can define the tensor product $V_1\otimes\cdots \otimes V_k$ by means of the universal property: it ...
Gold's user avatar
  • 37.4k
6 votes
1 answer
3k views

Scalar field transformation and generators

When we do a transformation (norm preserving one) for a given quantity, from what I have understood it seems like there is a representation of the group element for each quantity depending how they ...
user35952's user avatar
  • 3,134
6 votes
4 answers
7k views

What type of mathematical object is the "Pauli vector"?

The three pauli matrices $\sigma_x$, $\sigma_y$, $\sigma_z$ are sometimes combined in the "Pauli vector", usually denoted $\boldsymbol{\sigma} = \sigma_{x} \boldsymbol{e_x} + \sigma_y \boldsymbol{e_y} ...
Ignacio's user avatar
  • 1,320
4 votes
1 answer
5k views

Vector operators in quantum mechanics

Vector operators $\vec{V}$ in quantum mechanics are usually defined as those that commute in a particular way with the spatial Angular Momentum $\vec{L}$: $[L_i,V_j]=i\hbar\varepsilon_{ijk}V_k$. I am ...
crimson_sprite's user avatar
2 votes
3 answers
286 views

What does “transform among themselves” mean?

I'm reading a script on atomic physics, and there's a chapter on irreducible tensors. I can't understand the meaning of "transform among themselves" in this context: An arbitrary rotation of the ...
The Quantum Physicist's user avatar
0 votes
2 answers
1k views

What is $\vec \sigma$ in the context of spin?

Leonard susskind's book, quantum mechanics, the theoretical mimimum, statea that we can derive the spin operator $$\sigma_n=\sigma_x n_x + \sigma_y n_y + \sigma_z n_z$$ Where the $\sigma_i$ are spin ...
user56834's user avatar
  • 1,880
1 vote
1 answer
247 views

Commutation of abstract $O(3)$ generators and vectors [closed]

I've been given the following problem, and I'm quite lost with it. Let $L_1$, $L_2$, and $L_3$ denote the abstract $o(3)$ algebras. You are given that $\vec{A} = (A_1, A_2, A_3)$ and $\vec{B} = (B_1, ...
Jack's user avatar
  • 205
2 votes
1 answer
181 views

How is a tensor operator defined in terms of commutators?

If $J_i$ represent the angular momentum operators, then a scalar operator $S$ (rank-0 tensor) is defined as an operator which satisfies $$[S,J_i]=0$$ for $i=1,2,3$. $A_i$ is a vector (rank-1 tensor) ...
Solidification's user avatar