0
$\begingroup$

The general energy-momentum relation for a massless particle is $E=cp$.

I know that for a photon we have $E=hf$. Is this relation valid for any massless particle?

$\endgroup$
2
  • $\begingroup$ Why wouldn't it be? $E^2=p^2c^2+m^2c^4=p^2c^2\big|_{m=0}$, doesn't it? $\endgroup$ Commented Nov 23 at 21:51
  • $\begingroup$ What is the general energy expresion for a masless particle? In terms of what other quantities? $\endgroup$
    – Ghoster
    Commented Nov 23 at 21:58

1 Answer 1

4
$\begingroup$

The Planck relation $$E=hf$$ is valid for all particles, massive $(m\ne 0)$ and massless $(m=0)$.

The energy-momentum relation $$E^2=(cp)^2+(mc^2)^2$$ is valid for all particles. The relation $$E=cp$$ is just a special case of this, valid only for $m=0$.

$\endgroup$
1
  • $\begingroup$ Thank you Thomas. I read the link Planck relation. It is good to know that it was de Broglie who postulated the general validity of Planck's relation. $\endgroup$
    – facenian
    Commented Nov 23 at 22:57

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.