Apologies for the (hopefully now somewhat less) clickbait-y title. Now, of course, I know that the Big Bang did not happen at any point connected to a single point in our current $3$-dimensional observable universe by a one-dimensional causal curve. I also know that at any point in the universe, all other points seem to be moving away from that point. However, according to our current understanding of physics, the universe is (at least) $4$-dimensional. Just like how in the classical "balloon" analogy for an expanding universe, the points do in fact all move away from a common point on the interior of the balloon, all spacetime points do move away from the Big Bang, or at least some kind of cosmological horizon which surrounds it - this is how I understand going forward in time, at least. Does it make sense to think of this as a sort of "center" for the full, $4$-dimensional spacetime? Or are there further subtleties to this situation?
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1$\begingroup$ physics.stackexchange.com/q/136860 physics.stackexchange.com/q/91162 $\endgroup$– MithoronCommented May 20 at 13:42
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1$\begingroup$ physics.stackexchange.com/q/2378 physics.stackexchange.com/q/16074 $\endgroup$– MithoronCommented May 20 at 13:43
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1$\begingroup$ @Mithoron I looked at all of these before posting. They seem to be only concerned with the spatial part of spacetime, in terms of which the question makes no sense (I alluded to this in my question as well). I did not find a question which considered $4$-dimensional spacetime, and you did not link one either. $\endgroup$– paulinaCommented May 20 at 14:10
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4$\begingroup$ Does this answer your question? Does the universe have a center? $\endgroup$– MithoronCommented May 20 at 14:42
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1$\begingroup$ Voted to reopen because this is not a duplicate of the listed duplicate, nor of any of the questions linked. $\endgroup$– StenCommented May 20 at 22:40
3 Answers
There are two important points in here. The first was raised in a previous answer (and I'll comment on it also), but there is another nuance.
The Big Bang is not a point in spacetime
Yeah, that's pretty much it. The Big Bang is a singularity. The precise definition of a singularity is essentially that it is a "hole" in spacetime (you can see the rigorous definitions on the books by Wald or Hawking & Ellis). In the particular case of the FLRW model, the Big Bang singularity also involves curvature scalars diverging. Now, any point in the manifold must have well-defined metric and curvatures. It is not possible for the curvatures to diverge at any point: that would mean the manifold itself stops making sense at that "point", and hence it does not belong to the manifold.
This is very different from electromagnetism, for example, in which the electromagnetic field can diverge at a point. That is because the field is defined on top of spacetime and only the field is diverging. In general relativity, a curvature singularity means spacetime itself is "diverging", and there is no physically or mathematically meaningful way of considering that point as a point in spacetime.
The universe is not embedded in anything
This point was raised in another answer, and I'll try to address it with different words in here. I recently entered a discussion on Twitter about a SciComm article mentioning the universe might have the shape of a torus (a doughnut, in layman's terms), and a lot of confusion arose due to the question of "what lies in the empty space in the middle of the torus?". I can't help but notice the similarity of your balloon question with this question. I will discuss the torus example, because it has a wonderfully simple analogy that becomes a bit more intricate in the balloon case.
Both the balloon and our day-to-day experience of a torus are what we call embedded manifolds. I don't like the term embedding: in Portuguese we say "diving" (literal translation), which I think is more pictorial. You "dive" the space you are considering inside a larger space, just like a swimmer dives inside a pool. My point being that your pictorial vision of the balloon or of the doughnut is not of the object in and of itself, but rather of how it is embedded/inserted/depicted inside three-dimensional space. You only need two dimensions to describe the surface of the balloon or of the doughnut, but you add an extra one for the sake of visualization.
This is fine, and sometimes useful and interesting, but it has a problem: it introduces features that are due to the embedding, and not due to the space itself. When you look at the balloon, you are not only thinking about the balloon, but also about the way you inserted it in three-dimensional space. It is hard to separate which properties are due to the balloon and which are due to the embedding.
Now here's the reason I wanted to bring up the doughnut/torus: there is a beautiful visualization of a torus that does not depend on any particular embedding, and which is familiar to many people. Namely, the Pacman world. Pacman lives in a torus because when you go up the screen, you reappear at the bottom, and similar with the sides. Mathematically, these properties are (roughly speaking) what actually defines a torus. When we discuss spacetime, we are interested in these particular properties, not on how spacetime is embedded in a larger-dimensional space.
Now, with the Pacman example in mind, I ask you: what is in the "middle" of the torus? The answer is nothing. In fact, one could even question whether the question makes sense at all: there is no "middle". The "middle" only exists in your embedding, it is not a property of the torus.
What you found is a problem with the balloon visualization. It makes it seem as if there was some kind of center, but there isn't. That is a feature of the embedding, not of spacetime. If you think of spacetime in and of itself, the question doesn't even makes sense.
This is an important nuance in differential geometry and relativity. We always take an intrinsic point of view on spacetime, because it doesn't really make physical sense to imagine in what spacetime is embedded: we can't access this abstract region, so for all physical purposes it isn't real (and it is not unique mathematically, so there is no mathematical reason to expect it exists either). Without this embedding, the question disappears.
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1$\begingroup$ @paulina He talks about singularities on chapter 9. I know you can always embed a manifold in a higher-dimensional Euclidean space (this is Whitney's embedding theorem) and I believe you can do an isometric embedding with a Riemannian manifold (Nash embedding theorems), but I don't know if you can do it for a Lorentzian manifold. Maybe you can embed the smooth structure, but not the metric $\endgroup$ Commented May 18 at 17:31
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1$\begingroup$ @paulina If you care only about the smooth structure and not the precise behavior of the metric, then I believe the smooth structure for a closed universe which globally looks like $\mathbb{R} \times \mathbb{S}^3$ can be thought of as a sequence of nested three-spheres, and the Big Bang is the hole in the center. But this construction needs the universe to be spatially closed. $\endgroup$ Commented May 18 at 17:32
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1$\begingroup$ If consider a spatially flat universe (like ours, to the best of our knowledge) I don't see how one could nest Euclidean spaces as to get the Big Bang in the center $\endgroup$ Commented May 18 at 17:33
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2$\begingroup$ Asteroids is on a torus. en.wikipedia.org/wiki/Asteroids_(video_game) $\endgroup$– PM 2RingCommented May 19 at 4:33
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2$\begingroup$ @NíckolasAlves maybe they would prefer the term "diverges", but i have seen "blow up" used many times. $\endgroup$– paulinaCommented May 19 at 16:54
Some other answers say the universe isn't embedded in a background space, but I think that misses the point; the universe doesn't have to be embedded in anything for this idea to make sense. If the geometry of the universe at "time" $t$ were a sphere of radius $t$, and the metric were Euclidean (so the "time" direction was really another spatial direction), then the universe would just be 4D Euclidean space. It wouldn't be embedded in 4D Euclidean space, it would just be 4D Euclidean space (in polar coordinates, with a radial coordinate named $t$), and there would be no problem including the point at $t=0$ and calling it the center. I think that's the motivating example for this question.
It has been suggested that the early-time completion of the FLRW universe might have a Euclidean metric, or in other words that the universe "starts" Euclidean (as a gravitational instanton) and transitions somehow to Lorentzian "later". If that were the case then spacetime would have a well-defined center in a similar sense to the first paragraph—the unique fixed point of the homogeneity+isotropy symmetry group—and I would be completely on board with calling that the center of the universe, since the universe is spacetime.
But there's no evidence to support that idea and it has never been especially popular. In the much more popular inflationary models, a FLRW universe buds out of an almost-arbitrary seed state. The starting state probably doesn't have a well-defined center, or if it does the center needn't have any relationship to where the symmetries of the FLRW portion make it appear that a center ought to be.
Differential topology allows us to describe a 4 dimensional (3spatial+1temporal) space expanding without needing to embed it in a higher dimensional space. The balloon is a common metaphor for an expanding curved 2d space, but the fact that it is embedded in a 3d space and thus has a 3 dimensional center is an artifact of the balloon example rather than a fundamental aspect of the topology.
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$\begingroup$ I know this, however I take the third dimension in the ballon analogy to be time. Is this invalid? $\endgroup$– paulinaCommented May 18 at 16:15
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1$\begingroup$ I would suggest changing the first instance of “topology” to “geometry”, because topology cannot “see” expansion (a metric notion). $\endgroup$ Commented May 18 at 16:56