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Consider the single-hole diffraction of an electron. We can make the hole as small as we like and determine the electron's position with arbitrary accuracy. When it is in the hole, we can hit it with a low-energy photon, and measure its momentum.

There is no guarantee that the photon will strike the electron. But it "could". It seems that we can measure the position and momentum simultaneously if we are lucky. Does it mean UP has nothing to do with simultaneous measurements but only with statistical uncertainty?

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    $\begingroup$ I will clarify that the HUP doesn't just forbid simultaneous measurement of position and momentum. It states something far stronger -- that systems simply do not have a precise momentum and a position at the same time. The HUP has absolutely nothing to do with measurement. $\endgroup$
    – Prahar
    Commented Aug 26, 2023 at 11:52
  • $\begingroup$ The uncertainity principle as usually stated, the Kennard--Weyl relation, is statistical in nature. As for simultaneous measurements, the situation is different. See en.wikipedia.org/wiki/…. There are question discussing this on this site as well. I'll link them after I find them. $\endgroup$ Commented Aug 26, 2023 at 12:52
  • $\begingroup$ Related: physics.stackexchange.com/a/623184/81224 and physics.stackexchange.com/a/169736/81224. $\endgroup$ Commented Aug 26, 2023 at 12:59
  • $\begingroup$ @Prahar Whether the systems actually possess simultaneous position and momentum is an interpretation dependent statement. You should instead say that the wavefunction of the system cannot simultaneously be an eigenstate of position and momentum. HUP is a theorem about the wavefunction's standard deviations in position and momentum. $\endgroup$
    – Ryder Rude
    Commented Aug 26, 2023 at 13:00
  • $\begingroup$ @Prahar physics.stackexchange.com/a/600015/81224. From that answer "There is a sense in which a simultaneous and arbitrarily precise measurement of position and momentum is not only possible, but also routinely made in many quantum labs, for example quantum-optics labs. Such measurement is indeed at the core of modern quantum applications such as quantum-key distribution." $\endgroup$ Commented Aug 26, 2023 at 13:08

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For the photon to resolve the hole, it has to have a wavelength smaller than the hole, which gives it a momentum on the order of the momentum uncertainty caused by the hole, defeating the purpose of a low energy photon in the first place.

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  • $\begingroup$ "For the photon to resolve the hole". Is there no way that the photon interacts with the electron? Doesn't the interaction happen at a point? $\endgroup$
    – asim dahal
    Commented Aug 27, 2023 at 5:09
  • $\begingroup$ What makes you think the interaction is at a point? $\endgroup$
    – JEB
    Commented Aug 27, 2023 at 14:29
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Long story short: No, unfortunately not because you would measure random momentum with each new measurement.

Kudos for your curiosity and your Gedankenexperiment though.


The idea behind your measurement might be that you measure the momentum once via observation with a photon and then you know the momentum for each electron in a consecutive measurement. I hope that I got your point right.

In this case you would nevertheless not be able to infer information from your measurement because at the time of measurement the electron would have arbitrary momentum.

So assume a measurement is down at time $t_1$ resulting in momentum $p_1$. The next electron you measure at $t_2$ with momentum $p_2$ you could not causate latter momentum with former momentum as the difference in momentum is arbitrary due to HUP.

So even if you could do those measurements you would not be able to gather some causally linked information from this other than HUP meaning your measured momenta were to be distributed.

But, and this has to be stressed, you could not perform any predictions on the momenta of electrons going through the hole that you described.

In fact HUP is even more general than just momentum and position.

It is a result from the Cauchy Schwarz inequality. The Cauchy Schwarz inequality basically states that the projection of one vector upon another vector is less than the product of the individual lengths of the vectors.

But this means that a formulation analogous to HUP for momentum an d position can be found for many pairs of variables. These pairs in turn are called conjugated variables(wiki).

To answer your question: No, it is not possible to measure $\underline{\text{the momentum}} $ in your Gedankenexperiment in a way that the data you collect can be interpreted apart from random fluctuations.

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  • $\begingroup$ "Long story short: No, unfortunately not because you would measure random momentum with each new measurement." Yes, that's what I mean by "statistical uncertainty". $\endgroup$
    – asim dahal
    Commented Aug 26, 2023 at 14:33

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