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Consider $2$ ideal and identical gases $A$ and $B$ which are at the same initial state of ($P_1$,$V_1$,$T_1$).

$A$ is taken through a reversible adiabatic process and $B$ through an irreversible adibatic process. Since both a reversible and irreversible adiabatic process can't occur between the same initial and final equilibrium states, compare:-

a)Their final volumes and temperatures if their final pressures are the same

b)Their final pressures and temperatures if their final volumes are the same

c)Their final pressures and volumes if their final temperatures are the same

I have found a method by comparing $W_{rev}$ and $W_{irrev}$ but it is too tedious.Although, comparing $W_{rev}$ and $W_{irrev}$ elegantly proves that "both a reversible and irreversible adiabatic process can't occur between the same intial and final equilibrium states" as in this answer, to compare the final pressures/volumes/temperatures requires me to make several cases which is too tedious. So, I was looking for a more direct approach.

P.S. I'm a high school student. Please answer in simple language and in minute detail.

Addendum:Please consider the piston to be massless and the irreversible adiabatic process to be single step.

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  • $\begingroup$ Are you also comparing expansion vs compression, or just looking at expansion? $\endgroup$
    – Chet Miller
    Commented Jul 10, 2022 at 14:09
  • $\begingroup$ @ChetMiller Both $\endgroup$
    – Boson
    Commented Jul 10, 2022 at 14:09
  • $\begingroup$ @ChetMiller Also, please assume a massless piston. $\endgroup$
    – Boson
    Commented Jul 10, 2022 at 14:11
  • $\begingroup$ Are you also assuming that the irreversible paths occur at constant external pressure (after an initial sudden pressure decrease or increase)? $\endgroup$
    – Chet Miller
    Commented Jul 10, 2022 at 14:14
  • $\begingroup$ @ChetMiller Yes, only a single-step irreversible adiabatic process. $\endgroup$
    – Boson
    Commented Jul 10, 2022 at 14:20

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